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anonymous
 4 years ago
prove, f(x)=xcos1/x (when x not = 2)
=0 (when x=0)
f(x) is continuous at the point x=0
anonymous
 4 years ago
prove, f(x)=xcos1/x (when x not = 2) =0 (when x=0) f(x) is continuous at the point x=0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is your function f(x)=xcos(1/x) (when x not 0) =0 when x=0 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes yes. i am wrong xnot 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0+}xcos(1/x)=\lim_{x \rightarrow 0}xcos(1/x)=f(0)=0\] hence continuous at x=0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you are wondering why \[\lim_{x \rightarrow 0+}xcos(1/x)=0\] then note that \[1\leq \cos(1/x)\leq 1\ for\ all\ x.\] So \[\lim_{x \rightarrow 0}xcos(1/x)=\lim_{x \rightarrow 0}x\cdot a=a \lim_{x \rightarrow 0}x=0\] here a is any real value between 1 and 1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in which class u are?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0me in college 1st year:) which city u?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whic school..i am in kolkata

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cbse? if u need help regarding math problems u can ask me! i can suggest a great math book for classes 11 and 12!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh , say the name.can u suggest some books for mathematical olympiad?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah! I am in Jadavpur University (Mech Engg) for school to IIT level problems: Problems Plus In IIT Mathematics by Asit Dasgupta

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the book by asit dasgupta is great for the basics but for RMO,INMO u need to try some other books...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did u appear for RMO/INMO any time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes one time in class 11:was not well prepared:( didnt get through...u need tough preparations for RMO...however if u r a genius u dont need much preparataions!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are u good in probability?it is tough to me.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have no hard problem at present.when i found a very hard problem,i would ask u .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u can call me (if u want my cell no. u can ask me now) or u can mail me to saubhik.mukherjee@gmail.com...i dont come to openstudy often..so u can take my phone no. or gmail

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok.i will mail u.however do u have interest in astrophysics.it is my most fav.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0about me: i got 100 in maths in class 12 and 100 in class 10 CBSE. I love olympiad mathematics and want to help anyone interested in olympiad maths. about astrophysics:there is an olympiad for that and I dont know anything about it :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow.u r so brilliant!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks.hope to help u soon :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in triangle ABC,AB=AC,A is right angle.M & N are 2points on BC satisfying BM^2+CN^2=MN^2. prove that angle MAN=45.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I proved it using coordinate geometry. Did not get a good pure geometry solution though. I can show you the proof. You can post this as a separate question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait...i will attach a picture wait 2 min.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did u see the picture? The side AB is on yaxis and AC is on xaxis...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i did and understand.thanks a lot !!!but whenever u get pure geometry solution please post,30 MEDALS for u.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i did not explain anything..u got it? u have to use the distance formula to obtain a relation and then use this relation in another equation which u will get by considering the angle between the two lines AM and AN, which u can get by considering the slopes of the two lines AM and AN. did u get this angle as 45 degrees?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what's your email id?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes my elder sister helped me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is chowdhurysaugata6@gmail.com ok

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok...any more problems u can always ask me:)
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