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Derive the formula for the axis of symmetry to a quadratic equation.
 2 years ago
 2 years ago
Derive the formula for the axis of symmetry to a quadratic equation.
 2 years ago
 2 years ago

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LagrangeSon678Best ResponseYou've already chosen the best response.0
you just helped someone find the vertex of a parabola using the formula and now you want somemone to derive it for you?
 2 years ago

101Ryan101Best ResponseYou've already chosen the best response.0
Anytime I write a question it usually "for fun".. :)
 2 years ago

101Ryan101Best ResponseYou've already chosen the best response.0
U surely don't HAVE to.. :)
 2 years ago

LagrangeSon678Best ResponseYou've already chosen the best response.0
okay thanks for the info
 2 years ago

ZakaullahUETBest ResponseYou've already chosen the best response.0
Find the derivative and equate it to zero solve for x to get ur ans
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
\[y=ax^2+bx+c\] \[y=a(x+\frac{b}{a})+c\] \[y=a(x+\frac{b}{2a})^2+\color{red}{\text{who cares}}\] since first term is a perfect square it will be greater than or equal to zero if a is positive, less that or equal to zero if a is negative and it will be zero (so that is the max or min) if \[x=\frac{b}{2a}\]
 2 years ago

101Ryan101Best ResponseYou've already chosen the best response.0
If you don't care BOUNCE
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
i don't care because if i need to find it i can alway replace x by \[\frac{b}{2a}\] i just don't care to try to keep track of what i added and subtracted. waste of time since i can find it easily
 2 years ago
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