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101Ryan101

  • 3 years ago

Derive the formula for the axis of symmetry to a quadratic equation.

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  1. LagrangeSon678
    • 3 years ago
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    you just helped someone find the vertex of a parabola using the formula and now you want somemone to derive it for you?

  2. 101Ryan101
    • 3 years ago
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    Anytime I write a question it usually "for fun".. :)

  3. 101Ryan101
    • 3 years ago
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    U surely don't HAVE to.. :)

  4. LagrangeSon678
    • 3 years ago
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    okay thanks for the info

  5. ZakaullahUET
    • 3 years ago
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    Find the derivative and equate it to zero solve for x to get ur ans

  6. satellite73
    • 3 years ago
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    \[y=ax^2+bx+c\] \[y=a(x+\frac{b}{a})+c\] \[y=a(x+\frac{b}{2a})^2+\color{red}{\text{who cares}}\] since first term is a perfect square it will be greater than or equal to zero if a is positive, less that or equal to zero if a is negative and it will be zero (so that is the max or min) if \[x=-\frac{b}{2a}\]

  7. satellite73
    • 3 years ago
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    derivative my foot

  8. 101Ryan101
    • 3 years ago
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    If you don't care BOUNCE

  9. satellite73
    • 3 years ago
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    i don't care because if i need to find it i can alway replace x by \[-\frac{b}{2a}\] i just don't care to try to keep track of what i added and subtracted. waste of time since i can find it easily

  10. 101Ryan101
    • 3 years ago
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    I see.

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