## anonymous 5 years ago if log of 2 to the base 10=.301 log of 25 to the base 8=? show how to solve

1. anonymous

$\log_{10} 2 = .301$ $\log_{8} 25 = \frac{\log 25}{\log 8} = \frac{1.398}{.903} = 1.548$ Basically use change of base formula $\log_{b} x = \frac{\log x}{\log b}$

2. anonymous

hah! you can't do that?

3. anonymous

$\log_{8}25=2\log_{10}5/3\log_{10}2=2(1-\log_{10}2)/3\log_{10}2=2*(1-.301)/(3*.301)=1.548$

4. anonymous

very nice :)