AravindG
A block of mass M is pulled along a frictionless surface by a rope of mass m.If a force P is applied at the free end of rope ,What will be the force exerted by the rope on the block???
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101Ryan101
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As the rope pulls the block, the block pulls back with equal force in the opposite direction. So I'll go with 2p. But I'm not sure of that.. Anyone?
101Ryan101
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wait that's not right...
101Ryan101
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F=ma
Ishaan94
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see just take mass of rope plus the block and then apply all formulas
Ishaan94
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like joint bodies
Ishaan94
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they have reaction forces between them
101Ryan101
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(M+m)a = p
101Ryan101
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?
Ishaan94
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 r  <rope

 r  < block so r is the force exerted by the rope on the block
r = m(block)a and from the rope equation
Ishaan94
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f (force applied ) + r = m(rope)a
now get r
101Ryan101
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Maybe I should thing twice about taking physics. lol
Ishaan94
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lol
no you should take it
101Ryan101
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I don't really understand why its F+r on the left side there..
Ishaan94
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the thing is
block
 rope

R< > R



Ishaan94
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R is the reaction force or contact force
Ishaan94
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>R >p

P + r = m(rope)a
101Ryan101
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Are we speaking of the force the rope is "feeling"?
Ishaan94
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Yeah
101Ryan101
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OHHHHH
Ishaan94
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I didn't draw the normal or perpendicular forces
101Ryan101
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but it says "what will be the force by the rope ON THE BLOCK.. lol so I thought that means, what the block is feeling>>
Ishaan94
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R is the force for the block from the rope
Ishaan94
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now take a careful look the only force that rope and block have is the R so hence r is the one were looking for
101Ryan101
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Is there a name for this type of problem so I can go concentrate on them?
Ishaan94
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try Ropmass.......... I don't know i didn't solve them much