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A block of mass M is pulled along a frictionless surface by a rope of mass m.If a force P is applied at the free end of rope ,What will be the force exerted by the rope on the block???

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As the rope pulls the block, the block pulls back with equal force in the opposite direction. So I'll go with 2p. But I'm not sure of that.. Anyone?
wait that's not right...

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Other answers:

see just take mass of rope plus the block and then apply all formulas
like joint bodies
they have reaction forces between them
(M+m)a = p
| r | <-------rope -------- | r | < --------block so r is the force exerted by the rope on the block r = m(block)a and from the rope equation
f (force applied ) + r = m(rope)a now get r
Maybe I should thing twice about taking physics. lol
lol no you should take it
I don't really understand why its F+r on the left side there..
the thing is block | rope |---------------------- R<-| ---------> R |---------------------- | --------------------------------------------------
R is the reaction force or contact force
------------------------------------ ---->R |--------->p ------------------------------------ P + r = m(rope)a
Are we speaking of the force the rope is "feeling"?
I didn't draw the normal or perpendicular forces
but it says "what will be the force by the rope ON THE BLOCK.. lol so I thought that means, what the block is feeling>>
R is the force for the block from the rope
now take a careful look the only force that rope and block have is the R so hence r is the one were looking for
Is there a name for this type of problem so I can go concentrate on them?
try Rop-mass.......... I don't know i didn't solve them much

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