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marcfranzblau
Group Title
Solve. (2x^2)  8x 14 = 0
1) x= 4± 3 √2
2) x= 2± 2 √7
3) x= 4± √3
4) x= 2 ± √11
 3 years ago
 3 years ago
marcfranzblau Group Title
Solve. (2x^2)  8x 14 = 0 1) x= 4± 3 √2 2) x= 2± 2 √7 3) x= 4± √3 4) x= 2 ± √11
 3 years ago
 3 years ago

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101Ryan101 Group TitleBest ResponseYou've already chosen the best response.1
judging by the answers I guess you could use the quadratic equation.
 3 years ago

101Ryan101 Group TitleBest ResponseYou've already chosen the best response.1
wait.. ha ha.. divide the whole thing by 2
 3 years ago

101Ryan101 Group TitleBest ResponseYou've already chosen the best response.1
and it'll be x^2  4x 7
 3 years ago

marcfranzblau Group TitleBest ResponseYou've already chosen the best response.0
so could you tell me which is the best possible answer? i have no clue
 3 years ago

101Ryan101 Group TitleBest ResponseYou've already chosen the best response.1
The one that is the correct answer. :p
 3 years ago

101Ryan101 Group TitleBest ResponseYou've already chosen the best response.1
you have to use the quadratic formula... what you have is... x^2  4x 7 and the quadratic formula is...
 3 years ago

101Ryan101 Group TitleBest ResponseYou've already chosen the best response.1
ax^2 + bx + c is the form we have... (1)x^2  4x 7 where a =1 b = (4) c = (7)
 3 years ago

101Ryan101 Group TitleBest ResponseYou've already chosen the best response.1
plug a,b, and c into the quadratic equation to solve for the roots of x.. these are the points on the graph where this function crosses the x axis...
 3 years ago

marcfranzblau Group TitleBest ResponseYou've already chosen the best response.0
im trying i suck at this
 3 years ago

marcfranzblau Group TitleBest ResponseYou've already chosen the best response.0
You cant just help out a pal? one question ):
 3 years ago

marcfranzblau Group TitleBest ResponseYou've already chosen the best response.0
i got 4±√44 / 2 so far
 3 years ago
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