boog1
apply the quadratic formula to find the roots of the given function, and then graph the function
f(x)=y^2-9
please show work for credit
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101Ryan101
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OM goodness! :/
boog1
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lol
boog1
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thats what i said
101Ryan101
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ha ah.. Hey, are you sure that's written correctly? :/
101Ryan101
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usually it's f(x) = x^2 - 9
101Ryan101
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not y^2 - 9
boog1
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f(x) = x^2 - 9
101Ryan101
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ok, soooooo. huh... I guess f(x) = x?? lol
boog1
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i am having problems figuring out a b c for the formula
101Ryan101
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weird. then it should be f(y) = y^2 -9 because we are dealing with a function of y
boog1
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it is changed to x
boog1
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f(x) = x^2 - 9
101Ryan101
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AND there is no need to use the quadratic because you can factor this!
x^2 - 9 = x^2 - 3^2 = (x+3) (x-3)
so x is simply plus or minus 3!
use the quadratic? for what! lol
boog1
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finding the roots
101Ryan101
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well, the roots are -3 and 3 but anywyay with the quadratic you want to use
(1)x^2 + 0x - 9
a = 1
b = 0
c = -9
boog1
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ok now I think I got it from there