sabrinaandkay
(2√7)² simplifed with work



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Fred111
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\[\sqrt{(2\sqrt{7)^2}} > 2\sqrt{7}\]

sabrinaandkay
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wait that doesn't make sense

abhisheksingh59
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(2√7)² =2^2*7=4*7=28

sabrinaandkay
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how do you get 4 times 7?

Fred111
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2^2 =4 \[(\sqrt{7})^2=7\]