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## anonymous 5 years ago how to find this limit: lim (xˆ2-1)/(x-1) when x goes to 1?

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1. anonymous

2 is the answer

2. anonymous

2 because:$\frac{x^2-1}{x-1} = \frac{(x-1)(x+1)}{x-1} = x+1$

3. anonymous

(x^2-1)/(x-1) (x-1)(x+1)/(x-1) (x+1) after applying limit x goes to 1 we have answer is 2

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