Here's the question you clicked on:
giu
how to find this limit: lim (xˆ2-1)/(x-1) when x goes to 1?
2 is the answer
2 because:\[\frac{x^2-1}{x-1} = \frac{(x-1)(x+1)}{x-1} = x+1\]
(x^2-1)/(x-1) (x-1)(x+1)/(x-1) (x+1) after applying limit x goes to 1 we have answer is 2