Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.1
we want to show the second part?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
what is T?
 2 years ago

abichu Group TitleBest ResponseYou've already chosen the best response.0
PT= PROVE THAT
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
so we get to suppose \[\sec(\theta)+\tan(\theta)=P\] and we want to show \[PT \sin(\theta)=\frac{P^21}{P^2+1}\]?
 2 years ago

abichu Group TitleBest ResponseYou've already chosen the best response.0
and guys can you answer my prev.Questions too?! please..
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\sec(\theta)+\tan(\theta)=\frac{1}{\cos(\theta)}+\frac{\sin(\theta)}{\cos(\theta)}=\frac{1+\sin(\theta)}{\cos(\theta)}=P\] thinking....
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{1+\sin(\theta)}{\cos(\theta)}*\frac{1\sin(\theta)}{1\sin(\theta)}=\frac{1\sin^2(\theta)}{\cos(\theta)(1\sin(\theta))}\] \[=\frac{\cos^2(\theta)}{\cos(\theta)(1\sin(\theta))}=\frac{\cos(\theta)}{1\sin(\theta)}=P\] hmmm....
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
i havent solved it yet
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
maybe i should try this on paper first
 2 years ago

abichu Group TitleBest ResponseYou've already chosen the best response.0
what bout my prev.sums? can you solve it?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
let me try this one first
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
if \[\sec(\theta)+\tan(\theta)=P\] then \[(\sec(\theta)+\tan(\theta))(\sec(\theta)\tan(\theta))=P(\sec(\theta)\tan(\theta))\] but \[(\sec(\theta)+\tan(\theta))(\sec(\theta)\tan(\theta))=\sec^2(\theta)\tan^2(\theta)=1\] so we have \[1=P(\sec(\theta)\tan(\theta))\] => \[\sec(\theta)\tan(\theta)=\frac{1}{P}\] lets see if we can use this
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
lets see we have that \[\sec(\theta)+\tan(\theta)=\frac{1+\sin(\theta)}{\cos(\theta)}\] and \[\sec(\theta)\tan(\theta)=\frac{1\sin(\theta)}{\cos(\theta)}\] adding these together we get \[\frac{1+\sin(\theta)}{\cos(\theta)}+\frac{1\sin(\theta)}{\cos(\theta)}=P+\frac{1}{P}\] \[\frac{2}{\cos(\theta)}=\frac{P^2+1}{P}\] \[\frac{2P}{P^2+1}=\cos(\theta)\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
but if we imagine we have a right triangle and we draw theta somewhere then cos tells adj/hyp=2p/(P^2+1) we can find the opposite of side of theta opp^2+adj^2=hyp^2 \[opp^2=hyp^2adj^2=(P^2+1)^2(2P)^2=P^4+2P^2+12^2P^2\] so we have \[opp=\sqrt{P^42P^2+1}\] but sin=opp/hyp
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\sin(\theta)=\frac{\sqrt{P^42P^2+1}}{P^2+1}=\frac{\sqrt{(P^21)^2}}{P^2+1}\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\sin(\theta)=\frac{P^21}{P^2+1}\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
any questions?
 2 years ago

abichu Group TitleBest ResponseYou've already chosen the best response.0
yea..can you solve the other problems?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
i was looking for someone
 2 years ago

abichu Group TitleBest ResponseYou've already chosen the best response.0
and can you temme one thing..can you temme the stepin correct order so that i can copy it in my rough boook! ;)
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
hey zarkon i had to think on it isn't that crazy?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
the problem
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
trying to think if there is an easier way
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
i have no clue it was hard for me to see that way
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
what is temme?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
i don't know that word
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
use small words please lol
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
well i mean i guess its small but i don't know it
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
temme=tell me?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
i thought i showed u the steps zarkon thinks there may be an easier way though
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
zarkon i did this for you :)
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
how about this...
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
and for abichu dont feel left out
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
get to \[\frac{1+sin(\theta)}{\cos(\theta)}=p\] ...
 2 years ago

abichu Group TitleBest ResponseYou've already chosen the best response.0
i am soo weak in math..that's why am seeking help from you guys! if you dont mind help me! ;)
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
we are helping
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[1+\sin(\theta)=p\cos(\theta)\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
i showed you one way and zarkon is gonna show you another it appears
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[1+\sin(\theta)=p\sqrt{1\sin^2(\theta)}\]
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
square both sides...
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
omg i see where you are going
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[1+2\sin(\theta)+\sin^2(\theta)=p^2(1\sin^2(\theta))\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you going to write is as a quadratic
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
and solve for sin(theta)
 2 years ago

abichu Group TitleBest ResponseYou've already chosen the best response.0
can you tel me from the 1st step if you dot mind?!
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
move stuff to one side \[1p^2+2\sin(\theta)+(1+p^2)\sin^2(\theta)=0\]
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
brillant!
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[1p^2+2x+(1+p^2)x^2=0\]
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
solve this quadratic ;)
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
fun stuff :)
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
you are a showoff lol
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
lol...now abichu has two ways to do it
 2 years ago

abichu Group TitleBest ResponseYou've already chosen the best response.0
i donno how to solve it quadratic..can you doo it n give?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[x=\frac{2 \pm \sqrt{(2)^24(1+p^2)(1p^2)}}{2(1+p^2)}\]
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.