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is the polynomial written correctly?

woops my bad sorry
P(x) = x^3 +rx^2 +sx +t

Colorful pi can you help me?

let me try to help him and then i will look at your question

him ? are yu referring to me ?

is this algebra?

noo , its a polynomial question

so what class is it then?

class ? what do yu mean ? Its from the topic polynomials

\[P(x)=(x-1)(x-a)(x+a)=x^3+rs^2+sx+t\]

is that the answer ?

no , im not doing it for fun , its my maths assignment LOL

\[P(x)=x(x^2-a^2)-1(x^2-a^2)=x^3+rsx^2+sx+t\]

so the class is called polynomials lol?

what does yu mean by class ?

\[P(x)=x^3-a^2x-x^2+a^2=x^3+rsx^2+sx+t\]
people go to class to learn and get assignments lol

no the class is called maths LOL

\[P(x)=x^3-x^2-a^2x+a^2=x^3+rsx^2+sx+t\]

2 unit maths to be specific

ok we are almost done with this problem
can you guess what to do next?

we want both sides to be the same

collecting like terms ?

they must be equal

so we need that for the other terms as well

we have
-1=rs
-a^2=s
a^2=t

I seriously think I'm being trolled here.. but just to ease my tired brain..
\[\sqrt{25} \ne -5\]

you are right polpak

wait , dnt yu factorise it further to (x^2-a^2)(x-1)

that =5

factor?

Someone was trying to tell me that it equals both 5 and -5

ok the objective is to find s+t

But I can only really prove it by going to the definition. Which they don't accept.

ohh yeah , my bad

Sorry for bothering you mimi, but myin rarely watches group chat (with good reason)

yu talking to me or polpak ? LOL

you

lols , tbh im lost , i dont get it xDD

do you understand when I wrote P
as P(x)=(x-1)(x-a)(x+a)?

yeah , i dont understand the part
-1 = rs
-a^2 = s
a^2 = t
where did yu get it from ?

both sides had to be equal we were looking at
\[P(x)=x^3-a^2x-x^2+a^2=x^3+rsx^2+sx+t \]

ohh i get it
rs = -1

x on the left hand side: 1 i think
x on the right hand side 1 i think

no what is the number in front of x on boths?

both sides*

there's no other number

-a^2?
s?

lols , its a letter not a number

they are numbers

they are ? arent they are called pronumerals ?

are they*

never heard of this term

ohh ok

becauce a and i can be words

ohh ok , i never knew that they are numbers xD

but usually the book will make it clear to you what they are

yep

ok , so x= a^3

a^3 is nowhere to be found
we aren;t solving equation for x

ok , so x= a^3

ohh ok

ok so look again at the polynomial
what is the coefficent of x on both sides?

ok , so x= a^3

ok , so x= a^3

x= s

ok no
\[P(x)=x^3-a^2x-x^2+a^2=x^3+rsx^2+sx+t \]
^ ^
| |
-a^2 = s

ok , so x= a^3

ohh lols , sorry im so slow of understanding it

god my english is getting bad

ok , so x= a^3

lols , probably getting annoyed of me not getting it xD

no its just late here
i been up for along time today

a long*

Ditto!

so what are the constants on both sides?

the terms that don't have a x in them

ok , so x= a^3

t

ok , so x= a^3

t and what is it on the other side?

remember you are looking for non-x terms

ok , so x= a^3

a

a or a^2?

a

\[P(x)=x^3-a^2x-x^2+a^2=x^3+rsx^2+sx+t \]
^ ^
| |
a^2 = t

a^2 my bad

so what is s again?
and what is t again?

s = 1
t = a^2

s is not 1

a^3

not a^3
scroll up
we have it above

-a^2

lolss , im so~ slow

YES! :)

lols , finally i get it

ok now s+t is -a^2+a^2 right?

yeah

but what is -a^2+a^2?

so substitute it in s and t

idk

-5+5 is

-6+6 is
-24+24 is
-999+999 is

where did 5 come from ?

i'm just trying to help you think what -a^2+a^2 is

0 ?

yes! :)

and now you are done

really ? omg ! yay i got it right xD

thank you very mcuh for helping (:

np