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Mimi_x3 Group Title

Can you please help me with this maths question 1. The cubic polynomial P(x)= x^3 +rs^2 +sx+t , where r,s and t are real numbers has three real zeroes,1,a, and -a (a) find the value of s + t

  • 2 years ago
  • 2 years ago

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  1. myininaya Group Title
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    is the polynomial written correctly?

    • 2 years ago
  2. Mimi_x3 Group Title
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    woops my bad sorry P(x) = x^3 +rx^2 +sx +t

    • 2 years ago
  3. helpme1234 Group Title
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    Colorful pi can you help me?

    • 2 years ago
  4. myininaya Group Title
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    let me try to help him and then i will look at your question

    • 2 years ago
  5. Mimi_x3 Group Title
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    him ? are yu referring to me ?

    • 2 years ago
  6. myininaya Group Title
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    is this algebra?

    • 2 years ago
  7. Mimi_x3 Group Title
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    noo , its a polynomial question

    • 2 years ago
  8. myininaya Group Title
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    so what class is it then?

    • 2 years ago
  9. Mimi_x3 Group Title
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    class ? what do yu mean ? Its from the topic polynomials

    • 2 years ago
  10. myininaya Group Title
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    \[P(x)=(x-1)(x-a)(x+a)=x^3+rs^2+sx+t\]

    • 2 years ago
  11. Mimi_x3 Group Title
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    is that the answer ?

    • 2 years ago
  12. myininaya Group Title
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    so I guess you are doing it for fun? \[P(x)=(x-1)(x^2-a^2)=x^3+rs^2+sx+t\] no i just thought u would like to see the steps

    • 2 years ago
  13. Mimi_x3 Group Title
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    no , im not doing it for fun , its my maths assignment LOL

    • 2 years ago
  14. myininaya Group Title
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    \[P(x)=x(x^2-a^2)-1(x^2-a^2)=x^3+rsx^2+sx+t\]

    • 2 years ago
  15. myininaya Group Title
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    so the class is called polynomials lol?

    • 2 years ago
  16. Mimi_x3 Group Title
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    what does yu mean by class ?

    • 2 years ago
  17. myininaya Group Title
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    \[P(x)=x^3-a^2x-x^2+a^2=x^3+rsx^2+sx+t\] people go to class to learn and get assignments lol

    • 2 years ago
  18. Mimi_x3 Group Title
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    no the class is called maths LOL

    • 2 years ago
  19. myininaya Group Title
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    \[P(x)=x^3-x^2-a^2x+a^2=x^3+rsx^2+sx+t\]

    • 2 years ago
  20. Mimi_x3 Group Title
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    2 unit maths to be specific

    • 2 years ago
  21. myininaya Group Title
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    ok we are almost done with this problem can you guess what to do next?

    • 2 years ago
  22. myininaya Group Title
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    we want both sides to be the same

    • 2 years ago
  23. Mimi_x3 Group Title
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    collecting like terms ?

    • 2 years ago
  24. myininaya Group Title
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    ok the the coefficient of x^2 on left hand side is -1 the coefficient of x^2 on the other sides is rs so what can you say about rs and -1?

    • 2 years ago
  25. myininaya Group Title
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    they must be equal

    • 2 years ago
  26. myininaya Group Title
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    so we need that for the other terms as well

    • 2 years ago
  27. myininaya Group Title
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    we have -1=rs -a^2=s a^2=t

    • 2 years ago
  28. polpak Group Title
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    I seriously think I'm being trolled here.. but just to ease my tired brain.. \[\sqrt{25} \ne -5\]

    • 2 years ago
  29. myininaya Group Title
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    you are right polpak

    • 2 years ago
  30. Mimi_x3 Group Title
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    wait , dnt yu factorise it further to (x^2-a^2)(x-1)

    • 2 years ago
  31. myininaya Group Title
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    that =5

    • 2 years ago
  32. myininaya Group Title
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    factor?

    • 2 years ago
  33. polpak Group Title
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    Someone was trying to tell me that it equals both 5 and -5

    • 2 years ago
  34. myininaya Group Title
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    ok the objective is to find s+t

    • 2 years ago
  35. polpak Group Title
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    But I can only really prove it by going to the definition. Which they don't accept.

    • 2 years ago
  36. Mimi_x3 Group Title
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    ohh yeah , my bad

    • 2 years ago
  37. polpak Group Title
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    Sorry for bothering you mimi, but myin rarely watches group chat (with good reason)

    • 2 years ago
  38. myininaya Group Title
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    what do you think s+t is based on what i gave you above? hint we don't need that first equation rs=-1

    • 2 years ago
  39. Mimi_x3 Group Title
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    yu talking to me or polpak ? LOL

    • 2 years ago
  40. myininaya Group Title
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    you

    • 2 years ago
  41. Mimi_x3 Group Title
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    lols , tbh im lost , i dont get it xDD

    • 2 years ago
  42. myininaya Group Title
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    do you understand when I wrote P as P(x)=(x-1)(x-a)(x+a)?

    • 2 years ago
  43. Mimi_x3 Group Title
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    yeah , i dont understand the part -1 = rs -a^2 = s a^2 = t where did yu get it from ?

    • 2 years ago
  44. myininaya Group Title
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    both sides had to be equal we were looking at \[P(x)=x^3-a^2x-x^2+a^2=x^3+rsx^2+sx+t \]

    • 2 years ago
  45. myininaya Group Title
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    look at the coefficients of each term on both sides we want each term to be the same as it is on the other side

    • 2 years ago
  46. myininaya Group Title
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    so if we look at the x^3's they are good they both have coefficient 1 what is the coefficient of x^2 on left hand side ? what is the coefficient of x^2 on right hand side?

    • 2 years ago
  47. Mimi_x3 Group Title
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    ohh i get it rs = -1

    • 2 years ago
  48. myininaya Group Title
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    yes now what is the coefficient of x on the left hand side? what is the coefficient of x on the right hand side?

    • 2 years ago
  49. Mimi_x3 Group Title
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    x on the left hand side: 1 i think x on the right hand side 1 i think

    • 2 years ago
  50. myininaya Group Title
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    no what is the number in front of x on boths?

    • 2 years ago
  51. myininaya Group Title
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    both sides*

    • 2 years ago
  52. Mimi_x3 Group Title
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    there's no other number

    • 2 years ago
  53. myininaya Group Title
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    -a^2? s?

    • 2 years ago
  54. Mimi_x3 Group Title
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    lols , its a letter not a number

    • 2 years ago
  55. myininaya Group Title
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    they are numbers

    • 2 years ago
  56. Mimi_x3 Group Title
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    they are ? arent they are called pronumerals ?

    • 2 years ago
  57. Mimi_x3 Group Title
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    are they*

    • 2 years ago
  58. myininaya Group Title
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    never heard of this term

    • 2 years ago
  59. Mimi_x3 Group Title
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    ohh ok

    • 2 years ago
  60. myininaya Group Title
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    when you are doing math and you don't see a word and you see a letter it usually represents a number unless it is the word a or i

    • 2 years ago
  61. myininaya Group Title
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    becauce a and i can be words

    • 2 years ago
  62. Mimi_x3 Group Title
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    ohh ok , i never knew that they are numbers xD

    • 2 years ago
  63. myininaya Group Title
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    but usually the book will make it clear to you what they are

    • 2 years ago
  64. myininaya Group Title
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    yep

    • 2 years ago
  65. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  66. myininaya Group Title
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    a^3 is nowhere to be found we aren;t solving equation for x

    • 2 years ago
  67. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  68. Mimi_x3 Group Title
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    ohh ok

    • 2 years ago
  69. myininaya Group Title
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    ok so look again at the polynomial what is the coefficent of x on both sides?

    • 2 years ago
  70. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  71. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  72. Mimi_x3 Group Title
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    x= s

    • 2 years ago
  73. myininaya Group Title
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    ok no \[P(x)=x^3-a^2x-x^2+a^2=x^3+rsx^2+sx+t \] ^ ^ | | -a^2 = s

    • 2 years ago
  74. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  75. Mimi_x3 Group Title
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    ohh lols , sorry im so slow of understanding it

    • 2 years ago
  76. myininaya Group Title
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    ok do you see the terms that don't an x in em? there terms are called constants and they must be equal of that we have the same polynomial on both sides

    • 2 years ago
  77. myininaya Group Title
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    god my english is getting bad

    • 2 years ago
  78. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  79. Mimi_x3 Group Title
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    lols , probably getting annoyed of me not getting it xD

    • 2 years ago
  80. myininaya Group Title
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    no its just late here i been up for along time today

    • 2 years ago
  81. myininaya Group Title
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    a long*

    • 2 years ago
  82. polpak Group Title
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    Ditto!

    • 2 years ago
  83. myininaya Group Title
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    so what are the constants on both sides?

    • 2 years ago
  84. myininaya Group Title
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    the terms that don't have a x in them

    • 2 years ago
  85. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  86. Mimi_x3 Group Title
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    t

    • 2 years ago
  87. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  88. myininaya Group Title
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    t and what is it on the other side?

    • 2 years ago
  89. myininaya Group Title
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    remember you are looking for non-x terms

    • 2 years ago
  90. Mimi_x3 Group Title
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    ok , so x= a^3

    • 2 years ago
  91. Mimi_x3 Group Title
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    a

    • 2 years ago
  92. myininaya Group Title
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    a or a^2?

    • 2 years ago
  93. Mimi_x3 Group Title
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    a

    • 2 years ago
  94. myininaya Group Title
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    \[P(x)=x^3-a^2x-x^2+a^2=x^3+rsx^2+sx+t \] ^ ^ | | a^2 = t

    • 2 years ago
  95. Mimi_x3 Group Title
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    a^2 my bad

    • 2 years ago
  96. myininaya Group Title
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    so what is s again? and what is t again?

    • 2 years ago
  97. Mimi_x3 Group Title
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    s = 1 t = a^2

    • 2 years ago
  98. myininaya Group Title
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    s is not 1

    • 2 years ago
  99. Mimi_x3 Group Title
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    a^3

    • 2 years ago
  100. myininaya Group Title
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    not a^3 scroll up we have it above

    • 2 years ago
  101. Mimi_x3 Group Title
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    -a^2

    • 2 years ago
  102. Mimi_x3 Group Title
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    lolss , im so~ slow

    • 2 years ago
  103. myininaya Group Title
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    YES! :)

    • 2 years ago
  104. Mimi_x3 Group Title
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    lols , finally i get it

    • 2 years ago
  105. myininaya Group Title
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    ok now s+t is -a^2+a^2 right?

    • 2 years ago
  106. Mimi_x3 Group Title
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    yeah

    • 2 years ago
  107. myininaya Group Title
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    but what is -a^2+a^2?

    • 2 years ago
  108. Mimi_x3 Group Title
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    so substitute it in s and t

    • 2 years ago
  109. Mimi_x3 Group Title
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    idk

    • 2 years ago
  110. myininaya Group Title
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    -5+5 is

    • 2 years ago
  111. myininaya Group Title
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    -6+6 is -24+24 is -999+999 is

    • 2 years ago
  112. Mimi_x3 Group Title
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    where did 5 come from ?

    • 2 years ago
  113. myininaya Group Title
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    i'm just trying to help you think what -a^2+a^2 is

    • 2 years ago
  114. Mimi_x3 Group Title
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    0 ?

    • 2 years ago
  115. myininaya Group Title
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    yes! :)

    • 2 years ago
  116. myininaya Group Title
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    and now you are done

    • 2 years ago
  117. Mimi_x3 Group Title
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    really ? omg ! yay i got it right xD

    • 2 years ago
  118. Mimi_x3 Group Title
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    thank you very mcuh for helping (:

    • 2 years ago
  119. myininaya Group Title
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    np

    • 2 years ago
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