Mimi_x3

Can you please help me with this maths question
1. Let P(x) = (x+1)(x-3)Q(x)+a(x+1)+b , where Q(x) is a polynomial and a and b are real numbers
When P(x) is divided by (x+1) the remainder is -11.
When P(x) is divided by (x-3) the remainder is 1.
(i) What is the value of b?
(ii) What is the remainder when P(x) is divided by (x+1)(x-3) ?

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Hashir

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you want complete solution or jst answer

Mimi_x3

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complete solution please xD

Hashir

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ok

saifoo.khan

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u helping?

Hashir

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p(-1)=b
but r=-11
therfore b=-11

Hashir

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now find a

Hashir

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p(3)=4a+b
b=-11 and R=1
1=4a-11
4a=12
a=3

Mimi_x3

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thanks (:

Hashir

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II)R=-11

Hashir

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no problem

Mimi_x3

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reason for r = -11

Hashir

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because R1xR2
R1=-11
R2=1
R=-11

Mimi_x3

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ohh yeah , thanks (:

Mimi_x3

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nahh

Hashir

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ok

Mimi_x3

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Hashir , btw the answer for (ii) is 3x-8 xD