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RizaldoBest ResponseYou've already chosen the best response.0
There are 3 or 1 possible negative roots
 2 years ago

satellite73Best ResponseYou've already chosen the best response.3
saifooooooooooo! you need a nap
 2 years ago

satellite73Best ResponseYou've already chosen the best response.3
if x > 3 this is \[x3+x6=0\] \[2x=9\] \[x=\frac{9}{2}\] that is one answer
 2 years ago

satellite73Best ResponseYou've already chosen the best response.3
if x <0 this is \[x+3x6=0\] \[2x=3\] \[x=\frac{3}{2}\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.3
and if 0 < x < 3 this is \[x+3+x6=0\] or \[3=0\] so there is no solution on that intervals
 2 years ago

satellite73Best ResponseYou've already chosen the best response.3
steps clear or not? you need to break up the absolute value into intervals where it is positive and negative. then get rid of absolute value signs and solve the linear equation
 2 years ago
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