anonymous
  • anonymous
roots of lx-3l+lxl-6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
There are 3 or 1 possible negative roots
anonymous
  • anonymous
saifooooooooooo! you need a nap
saifoo.khan
  • saifoo.khan
=(

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saifoo.khan
  • saifoo.khan
DANG!
anonymous
  • anonymous
if x > 3 this is \[x-3+x-6=0\] \[2x=9\] \[x=\frac{9}{2}\] that is one answer
saifoo.khan
  • saifoo.khan
second is -3/2
anonymous
  • anonymous
if x <0 this is \[-x+3-x-6=0\] \[-2x=3\] \[x=-\frac{3}{2}\]
anonymous
  • anonymous
and if 0 < x < 3 this is \[-x+3+x-6=0\] or \[-3=0\] so there is no solution on that intervals
anonymous
  • anonymous
steps clear or not? you need to break up the absolute value into intervals where it is positive and negative. then get rid of absolute value signs and solve the linear equation

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