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allanishur

  • 4 years ago

roots of lx-3l+lxl-6

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  1. Rizaldo
    • 4 years ago
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    There are 3 or 1 possible negative roots

  2. anonymous
    • 4 years ago
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    saifooooooooooo! you need a nap

  3. saifoo.khan
    • 4 years ago
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    =(

  4. saifoo.khan
    • 4 years ago
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    DANG!

  5. anonymous
    • 4 years ago
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    if x > 3 this is \[x-3+x-6=0\] \[2x=9\] \[x=\frac{9}{2}\] that is one answer

  6. saifoo.khan
    • 4 years ago
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    second is -3/2

  7. anonymous
    • 4 years ago
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    if x <0 this is \[-x+3-x-6=0\] \[-2x=3\] \[x=-\frac{3}{2}\]

  8. anonymous
    • 4 years ago
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    and if 0 < x < 3 this is \[-x+3+x-6=0\] or \[-3=0\] so there is no solution on that intervals

  9. anonymous
    • 4 years ago
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    steps clear or not? you need to break up the absolute value into intervals where it is positive and negative. then get rid of absolute value signs and solve the linear equation

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