allanishur
roots of lx-3l+lxl-6
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Rizaldo
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There are 3 or 1 possible negative roots
anonymous
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saifooooooooooo! you need a nap
saifoo.khan
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=(
saifoo.khan
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DANG!
anonymous
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if x > 3 this is
\[x-3+x-6=0\]
\[2x=9\]
\[x=\frac{9}{2}\] that is one answer
saifoo.khan
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second is -3/2
anonymous
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if x <0 this is
\[-x+3-x-6=0\]
\[-2x=3\]
\[x=-\frac{3}{2}\]
anonymous
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and if 0 < x < 3 this is
\[-x+3+x-6=0\] or
\[-3=0\] so there is no solution on that intervals
anonymous
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steps clear or not? you need to break up the absolute value into intervals where it is positive and negative. then get rid of absolute value signs and solve the linear equation