## 9970189 Group Title how do you derive velocity from the equation 8-6t+t^2? PLEASE EXPLAIN HOW YOU GOT THE ANSWER. Thanks. 3 years ago 3 years ago

since the acceleration function has already been giving as a=8-6t+t^2,we want to find velocity,it implies we have to integrate i.e a=8-6t+t^2 implies $v=\int\limits a dt = \int\limits (8-6t+t^2)dt$ . after integration this is what you get$c + 8t -3t^2 +t^3/3$ which becomes your velocity. now if you know your initial velocity and time that is V1 and T1 respectively you substitute into your velocity equation $v =c + 8t -3t^2 +t^3/3$ you can derive your constant "C". hence to find the second velocity all you have to do is substitute the time T2 of the second velocity into the equation.