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 3 years ago
Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States.
U. S. State 2008 Population
Missouri 5,911,605
Pennsylvania 12,448,279
Tennessee 6,214,888
Utah 2,736,424
Washington 6,549,224
SOURCE: U. S. Census Bureau
What is the probability that a randomly selected U.S. resident did not live in Missouri? Show step by step work. Round solution to the nearest thousandth.
please show work!
 3 years ago
Essay. According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States. U. S. State 2008 Population Missouri 5,911,605 Pennsylvania 12,448,279 Tennessee 6,214,888 Utah 2,736,424 Washington 6,549,224 SOURCE: U. S. Census Bureau What is the probability that a randomly selected U.S. resident did not live in Missouri? Show step by step work. Round solution to the nearest thousandth. please show work!

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IsthmusTutoring
 3 years ago
Best ResponseYou've already chosen the best response.0Take the probability that the resident did live in Missouri, then subtract that value from 1. Hence,\[1  5911605/303824640\] Use your calculator.

keebler01
 3 years ago
Best ResponseYou've already chosen the best response.0P=5,911,605/ 303,824,640= 0.019

keebler01
 3 years ago
Best ResponseYou've already chosen the best response.0still trying to figure this out !

imranmeah91
 3 years ago
Best ResponseYou've already chosen the best response.0do what isthmus said

lalaly
 3 years ago
Best ResponseYou've already chosen the best response.2Just subtract 5,911,605 from 303,824,640 and you get 297913035 . This number is equivalent to the number of residents that do not live in missourri 297913035 over 303,824,640 is 297913035 /303,824,640. This figure is the probability that a randomly selected U.S. resident did not live in missouri. The rough percentage probability is 98.05%. The decimal equivalent to the nearest thousandth is .981
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