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jbenes
 4 years ago
what is the limit as x>9 of (9x)/sqrt(x)3
jbenes
 4 years ago
what is the limit as x>9 of (9x)/sqrt(x)3

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LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.1perhaps you can multiply the top and bottom by the conjugate

Outkast3r09
 4 years ago
Best ResponseYou've already chosen the best response.0perhaps you are on the right track lagrangeson

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.1or we could factor out the top and bottom, yeah that sounds better

jbenes
 4 years ago
Best ResponseYou've already chosen the best response.0how would i factor the top? there are no exponents

Outkast3r09
 4 years ago
Best ResponseYou've already chosen the best response.0to check just use l'hopitals but 6 is incorrect you're losing a  somewhere

LagrangeSon678
 4 years ago
Best ResponseYou've already chosen the best response.1i made a mistake sorry

dinainjune
 4 years ago
Best ResponseYou've already chosen the best response.1{(9x)/sqrtx 3} x {sqrtx +3/ sqrt x + 3} {9sqrt x +27x sqrt x 3x} / {x9} { sqrt x (x9) 3 (x9)} / {x9} (x9) (sqrt x 3) / (x9) = sqrt x 3 =  sqrt 9 3 = 33 =6

jbenes
 4 years ago
Best ResponseYou've already chosen the best response.0ok thanks for all your help!

joemath314159
 4 years ago
Best ResponseYou've already chosen the best response.0lagrange had the right idea, there was just a sign mistake.
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