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LagrangeSon678Best ResponseYou've already chosen the best response.1
perhaps you can multiply the top and bottom by the conjugate
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
perhaps you are on the right track lagrangeson
 2 years ago

LagrangeSon678Best ResponseYou've already chosen the best response.1
or we could factor out the top and bottom, yeah that sounds better
 2 years ago

jbenesBest ResponseYou've already chosen the best response.0
how would i factor the top? there are no exponents
 2 years ago

Outkast3r09Best ResponseYou've already chosen the best response.0
to check just use l'hopitals but 6 is incorrect you're losing a  somewhere
 2 years ago

LagrangeSon678Best ResponseYou've already chosen the best response.1
i made a mistake sorry
 2 years ago

dinainjuneBest ResponseYou've already chosen the best response.1
{(9x)/sqrtx 3} x {sqrtx +3/ sqrt x + 3} {9sqrt x +27x sqrt x 3x} / {x9} { sqrt x (x9) 3 (x9)} / {x9} (x9) (sqrt x 3) / (x9) = sqrt x 3 =  sqrt 9 3 = 33 =6
 2 years ago

jbenesBest ResponseYou've already chosen the best response.0
ok thanks for all your help!
 2 years ago

joemath314159Best ResponseYou've already chosen the best response.0
lagrange had the right idea, there was just a sign mistake.
 2 years ago
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