anonymous
  • anonymous
what is the limit as x->9 of (9-x)/sqrt(x)-3
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
perhaps you can multiply the top and bottom by the conjugate
anonymous
  • anonymous
-6
anonymous
  • anonymous
perhaps you are on the right track lagrangeson

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anonymous
  • anonymous
=]
anonymous
  • anonymous
or we could factor out the top and bottom, yeah that sounds better
anonymous
  • anonymous
how would i factor the top? there are no exponents
anonymous
  • anonymous
it's -6
saifoo.khan
  • saifoo.khan
-_-
anonymous
  • anonymous
to check just use l'hopitals but 6 is incorrect you're losing a - somewhere
anonymous
  • anonymous
i made a mistake sorry
anonymous
  • anonymous
{(9-x)/sqrtx -3} x {sqrtx +3/ sqrt x + 3} {9sqrt x +27-x sqrt x -3x} / {x-9} {- sqrt x (x-9) -3 (x-9)} / {x-9} (x-9) (-sqrt x -3) / (x-9) = -sqrt x -3 = - sqrt 9 -3 = -3-3 =-6
anonymous
  • anonymous
ok thanks for all your help!
anonymous
  • anonymous
lagrange had the right idea, there was just a sign mistake.

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