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x+square root of x=12

Mathematics
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That's not even the right question Kushash..
\[x+\sqrt{x}=12\]
\[\sqrt{x}=12-x=>(\sqrt{x})^2=(12-x)^2=>x=144-24x+x^2\]

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Other answers:

1 subtract x from both side 2 square both side
my thingy got cut off
Multiple lines is easier to read.
do i factor 0=x^2-24x+144
yes,
what add up to -24 and multiplies to 144?
kushash.. That is not the right problem. Seriously. Stop spamming.
kushashwa is half right. x can be 9. he put the answer for root(x).
i think it should be -25x in the middle
thats what i thought monkey
because you still have that other x on the left side
You can either factor it, or use the quadratic equation.
right and if you subract that x on both sides you have -24x-x
in which case it is 0=x^2-25x+144 which makes it more difficult
x^2-24x-x+144=0
so then i should use the quadratic equation to solve?
you can do factoring
(x-9)(x-16)=0
x = 9,16
you guys are awesome thank you
If it is something you cannot factor easily, using the quadratic formula always works. Even if it's factorable, sometimes you can't figure it out.

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