anonymous
  • anonymous
x+square root of x=12
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
That's not even the right question Kushash..
anonymous
  • anonymous
\[x+\sqrt{x}=12\]
anonymous
  • anonymous
\[\sqrt{x}=12-x=>(\sqrt{x})^2=(12-x)^2=>x=144-24x+x^2\]

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anonymous
  • anonymous
1 subtract x from both side 2 square both side
anonymous
  • anonymous
my thingy got cut off
anonymous
  • anonymous
Multiple lines is easier to read.
anonymous
  • anonymous
do i factor 0=x^2-24x+144
anonymous
  • anonymous
yes,
anonymous
  • anonymous
what add up to -24 and multiplies to 144?
anonymous
  • anonymous
kushash.. That is not the right problem. Seriously. Stop spamming.
anonymous
  • anonymous
kushashwa is half right. x can be 9. he put the answer for root(x).
anonymous
  • anonymous
i think it should be -25x in the middle
anonymous
  • anonymous
thats what i thought monkey
anonymous
  • anonymous
because you still have that other x on the left side
anonymous
  • anonymous
You can either factor it, or use the quadratic equation.
anonymous
  • anonymous
right and if you subract that x on both sides you have -24x-x
anonymous
  • anonymous
in which case it is 0=x^2-25x+144 which makes it more difficult
anonymous
  • anonymous
x^2-24x-x+144=0
anonymous
  • anonymous
so then i should use the quadratic equation to solve?
anonymous
  • anonymous
you can do factoring
anonymous
  • anonymous
(x-9)(x-16)=0
anonymous
  • anonymous
x = 9,16
anonymous
  • anonymous
you guys are awesome thank you
anonymous
  • anonymous
If it is something you cannot factor easily, using the quadratic formula always works. Even if it's factorable, sometimes you can't figure it out.

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