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lovehandles

  • 3 years ago

x+square root of x=12

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  1. polpak
    • 3 years ago
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    That's not even the right question Kushash..

  2. imranmeah91
    • 3 years ago
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    \[x+\sqrt{x}=12\]

  3. monkey131
    • 3 years ago
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    \[\sqrt{x}=12-x=>(\sqrt{x})^2=(12-x)^2=>x=144-24x+x^2\]

  4. imranmeah91
    • 3 years ago
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    1 subtract x from both side 2 square both side

  5. monkey131
    • 3 years ago
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    my thingy got cut off

  6. polpak
    • 3 years ago
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    Multiple lines is easier to read.

  7. lovehandles
    • 3 years ago
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    do i factor 0=x^2-24x+144

  8. imranmeah91
    • 3 years ago
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    yes,

  9. imranmeah91
    • 3 years ago
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    what add up to -24 and multiplies to 144?

  10. polpak
    • 3 years ago
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    kushash.. That is not the right problem. Seriously. Stop spamming.

  11. sparrowjay
    • 3 years ago
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    kushashwa is half right. x can be 9. he put the answer for root(x).

  12. monkey131
    • 3 years ago
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    i think it should be -25x in the middle

  13. lovehandles
    • 3 years ago
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    thats what i thought monkey

  14. lovehandles
    • 3 years ago
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    because you still have that other x on the left side

  15. polpak
    • 3 years ago
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    You can either factor it, or use the quadratic equation.

  16. monkey131
    • 3 years ago
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    right and if you subract that x on both sides you have -24x-x

  17. lovehandles
    • 3 years ago
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    in which case it is 0=x^2-25x+144 which makes it more difficult

  18. monkey131
    • 3 years ago
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    x^2-24x-x+144=0

  19. lovehandles
    • 3 years ago
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    so then i should use the quadratic equation to solve?

  20. monkey131
    • 3 years ago
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    you can do factoring

  21. monkey131
    • 3 years ago
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    (x-9)(x-16)=0

  22. Rizaldo
    • 3 years ago
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    x = 9,16

  23. lovehandles
    • 3 years ago
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    you guys are awesome thank you

  24. polpak
    • 3 years ago
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    If it is something you cannot factor easily, using the quadratic formula always works. Even if it's factorable, sometimes you can't figure it out.

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