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lovehandles

x+square root of x=12

  • 2 years ago
  • 2 years ago

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  1. polpak
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    That's not even the right question Kushash..

    • 2 years ago
  2. imranmeah91
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    \[x+\sqrt{x}=12\]

    • 2 years ago
  3. monkey131
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    \[\sqrt{x}=12-x=>(\sqrt{x})^2=(12-x)^2=>x=144-24x+x^2\]

    • 2 years ago
  4. imranmeah91
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    1 subtract x from both side 2 square both side

    • 2 years ago
  5. monkey131
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    my thingy got cut off

    • 2 years ago
  6. polpak
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    Multiple lines is easier to read.

    • 2 years ago
  7. lovehandles
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    do i factor 0=x^2-24x+144

    • 2 years ago
  8. imranmeah91
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    yes,

    • 2 years ago
  9. imranmeah91
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    what add up to -24 and multiplies to 144?

    • 2 years ago
  10. polpak
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    kushash.. That is not the right problem. Seriously. Stop spamming.

    • 2 years ago
  11. sparrowjay
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    kushashwa is half right. x can be 9. he put the answer for root(x).

    • 2 years ago
  12. monkey131
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    i think it should be -25x in the middle

    • 2 years ago
  13. lovehandles
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    thats what i thought monkey

    • 2 years ago
  14. lovehandles
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    because you still have that other x on the left side

    • 2 years ago
  15. polpak
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    You can either factor it, or use the quadratic equation.

    • 2 years ago
  16. monkey131
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    right and if you subract that x on both sides you have -24x-x

    • 2 years ago
  17. lovehandles
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    in which case it is 0=x^2-25x+144 which makes it more difficult

    • 2 years ago
  18. monkey131
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    x^2-24x-x+144=0

    • 2 years ago
  19. lovehandles
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    so then i should use the quadratic equation to solve?

    • 2 years ago
  20. monkey131
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    you can do factoring

    • 2 years ago
  21. monkey131
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    (x-9)(x-16)=0

    • 2 years ago
  22. Rizaldo
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    x = 9,16

    • 2 years ago
  23. lovehandles
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    you guys are awesome thank you

    • 2 years ago
  24. polpak
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    If it is something you cannot factor easily, using the quadratic formula always works. Even if it's factorable, sometimes you can't figure it out.

    • 2 years ago
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