lovehandles
x+square root of x=12



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polpak
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That's not even the right question Kushash..

imranmeah91
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\[x+\sqrt{x}=12\]

monkey131
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\[\sqrt{x}=12x=>(\sqrt{x})^2=(12x)^2=>x=14424x+x^2\]

imranmeah91
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1 subtract x from both side
2 square both side

monkey131
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my thingy got cut off

polpak
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Multiple lines is easier to read.

lovehandles
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do i factor 0=x^224x+144

imranmeah91
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yes,

imranmeah91
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what add up to 24 and multiplies to 144?

polpak
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kushash.. That is not the right problem. Seriously. Stop spamming.

sparrowjay
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kushashwa is half right. x can be 9. he put the answer for root(x).

monkey131
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i think it should be 25x in the middle

lovehandles
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thats what i thought monkey

lovehandles
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because you still have that other x on the left side

polpak
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You can either factor it, or use the quadratic equation.

monkey131
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right and if you subract that x on both sides
you have 24xx

lovehandles
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in which case it is 0=x^225x+144 which makes it more difficult

monkey131
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x^224xx+144=0

lovehandles
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so then i should use the quadratic equation to solve?

monkey131
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you can do factoring

monkey131
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(x9)(x16)=0

Rizaldo
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x = 9,16

lovehandles
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you guys are awesome thank you

polpak
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If it is something you cannot factor easily, using the quadratic formula always works. Even if it's factorable, sometimes you can't figure it out.