lisamarieee95
Simplify 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4.
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dinainjune
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64*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4.
or
6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 ?
Outkast3r09
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lol yes i find this confusin also lol
lisamarieee95
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the 6 and the 4 are separate. it's 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4. or 6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4
by the asteric i mean that the number before it is a small raised number.
Outkast3r09
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so the numers asterick are cube/4th roots yada yada?
lisamarieee95
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yup.
Outkast3r09
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so in other words it is this
\[6\sqrt[4]{4}\]
Outkast3r09
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as the first part?
lisamarieee95
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exactly!
Outkast3r09
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alright i'll equate it out for nick so he can make sure i'm sure he's got hte right answer
\[6\sqrt[4]{4}-8\sqrt[3]{4}+2\sqrt[3]{4}-3\sqrt[3]{4}\]
Nick_Black
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6*4√4 - 7 *3√4 + 2 *3√4 - 3 *3√4
3√4(6*√4-7+2-3)
3√4(6*√4-8)
Outkast3r09
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is that correct?
lisamarieee95
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yes. (:
Outkast3r09
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nick's answer is right or the way i showed it/
Nick_Black
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out u wrote 8 instead of 7
Nick_Black
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and 95 girl i am right i just simplified it
Nick_Black
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i took 3√4 common
Nick_Black
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out u do it too y will get the same one wht i got
Outkast3r09
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it's correct it just looks so weird when you use a check to show sqroot i see it as all under the root
Nick_Black
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its correct so i deserve a medal too bro
Outkast3r09
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lol