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Simplify 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4.

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64*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4. or 6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 ?
lol yes i find this confusin also lol
the 6 and the 4 are separate. it's 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4. or 6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 by the asteric i mean that the number before it is a small raised number.

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Other answers:

so the numers asterick are cube/4th roots yada yada?
so in other words it is this \[6\sqrt[4]{4}\]
as the first part?
alright i'll equate it out for nick so he can make sure i'm sure he's got hte right answer \[6\sqrt[4]{4}-8\sqrt[3]{4}+2\sqrt[3]{4}-3\sqrt[3]{4}\]
6*4√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 3√4(6*√4-7+2-3) 3√4(6*√4-8)
is that correct?
yes. (:
nick's answer is right or the way i showed it/
out u wrote 8 instead of 7
and 95 girl i am right i just simplified it
i took 3√4 common
out u do it too y will get the same one wht i got
it's correct it just looks so weird when you use a check to show sqroot i see it as all under the root
its correct so i deserve a medal too bro

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