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lisamarieee95

  • 3 years ago

Simplify 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4.

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  1. dinainjune
    • 3 years ago
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    64*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4. or 6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 ?

  2. Outkast3r09
    • 3 years ago
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    lol yes i find this confusin also lol

  3. lisamarieee95
    • 3 years ago
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    the 6 and the 4 are separate. it's 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4. or 6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 by the asteric i mean that the number before it is a small raised number.

  4. Outkast3r09
    • 3 years ago
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    so the numers asterick are cube/4th roots yada yada?

  5. lisamarieee95
    • 3 years ago
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    yup.

  6. Outkast3r09
    • 3 years ago
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    so in other words it is this \[6\sqrt[4]{4}\]

  7. Outkast3r09
    • 3 years ago
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    as the first part?

  8. lisamarieee95
    • 3 years ago
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    exactly!

  9. Outkast3r09
    • 3 years ago
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    alright i'll equate it out for nick so he can make sure i'm sure he's got hte right answer \[6\sqrt[4]{4}-8\sqrt[3]{4}+2\sqrt[3]{4}-3\sqrt[3]{4}\]

  10. Nick_Black
    • 3 years ago
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    6*4√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 3√4(6*√4-7+2-3) 3√4(6*√4-8)

  11. Outkast3r09
    • 3 years ago
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    is that correct?

  12. lisamarieee95
    • 3 years ago
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    yes. (:

  13. Outkast3r09
    • 3 years ago
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    nick's answer is right or the way i showed it/

  14. Nick_Black
    • 3 years ago
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    out u wrote 8 instead of 7

  15. Nick_Black
    • 3 years ago
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    and 95 girl i am right i just simplified it

  16. Nick_Black
    • 3 years ago
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    i took 3√4 common

  17. Nick_Black
    • 3 years ago
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    out u do it too y will get the same one wht i got

  18. Outkast3r09
    • 3 years ago
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    it's correct it just looks so weird when you use a check to show sqroot i see it as all under the root

  19. Nick_Black
    • 3 years ago
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    its correct so i deserve a medal too bro

  20. Outkast3r09
    • 3 years ago
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    lol

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