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lisamarieee95

Simplify 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4.

  • 2 years ago
  • 2 years ago

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  1. dinainjune
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    64*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4. or 6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 ?

    • 2 years ago
  2. Outkast3r09
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    lol yes i find this confusin also lol

    • 2 years ago
  3. lisamarieee95
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    the 6 and the 4 are separate. it's 6 4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4. or 6*4*√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 by the asteric i mean that the number before it is a small raised number.

    • 2 years ago
  4. Outkast3r09
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    so the numers asterick are cube/4th roots yada yada?

    • 2 years ago
  5. lisamarieee95
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    yup.

    • 2 years ago
  6. Outkast3r09
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    so in other words it is this \[6\sqrt[4]{4}\]

    • 2 years ago
  7. Outkast3r09
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    as the first part?

    • 2 years ago
  8. lisamarieee95
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    exactly!

    • 2 years ago
  9. Outkast3r09
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    alright i'll equate it out for nick so he can make sure i'm sure he's got hte right answer \[6\sqrt[4]{4}-8\sqrt[3]{4}+2\sqrt[3]{4}-3\sqrt[3]{4}\]

    • 2 years ago
  10. Nick_Black
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    6*4√4 - 7 *3√4 + 2 *3√4 - 3 *3√4 3√4(6*√4-7+2-3) 3√4(6*√4-8)

    • 2 years ago
  11. Outkast3r09
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    is that correct?

    • 2 years ago
  12. lisamarieee95
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    yes. (:

    • 2 years ago
  13. Outkast3r09
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    nick's answer is right or the way i showed it/

    • 2 years ago
  14. Nick_Black
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    out u wrote 8 instead of 7

    • 2 years ago
  15. Nick_Black
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    and 95 girl i am right i just simplified it

    • 2 years ago
  16. Nick_Black
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    i took 3√4 common

    • 2 years ago
  17. Nick_Black
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    out u do it too y will get the same one wht i got

    • 2 years ago
  18. Outkast3r09
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    it's correct it just looks so weird when you use a check to show sqroot i see it as all under the root

    • 2 years ago
  19. Nick_Black
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    its correct so i deserve a medal too bro

    • 2 years ago
  20. Outkast3r09
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    lol

    • 2 years ago
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