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jasleen727

  • 3 years ago

can someone show me how to find the zeros... f(x) =x^3+4x^2+4x. FIND the zeros of f.

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  1. Mybrainvsme
    • 3 years ago
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    set it = 0 so you can factoooorrrr

  2. Mybrainvsme
    • 3 years ago
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    and you can factor out an x from the get go!

  3. Mybrainvsme
    • 3 years ago
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    0= x(x²+4x-4)

  4. dinainjune
    • 3 years ago
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    right x(x^2+4x+4)=0 x(x+2)^2=0

  5. Mybrainvsme
    • 3 years ago
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    0=x(x +2) (x-2) x = 0 x = 2 x= -2 these are the zeros.

  6. dinainjune
    • 3 years ago
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    x=0, and x+2=0 is x=-2

  7. saifoo.khan
    • 3 years ago
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    f is written just beside x.

  8. Mybrainvsme
    • 3 years ago
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    lol yes, correct saifooooo.

  9. jasleen727
    • 3 years ago
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    ^im confused... >.<

  10. saifoo.khan
    • 3 years ago
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    are u?

  11. jasleen727
    • 3 years ago
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    NEVER MIND. got it! haha

  12. Mybrainvsme
    • 3 years ago
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    yayyyyyyyyyyy

  13. Nick_Black
    • 3 years ago
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    yo

  14. jasleen727
    • 3 years ago
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    sup

  15. jasleen727
    • 3 years ago
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    im not so good at graphs..so.. f(x)=1-3^x the graph of f is reflected over the line y=x. what is the name of function of the new graph?

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