anonymous
  • anonymous
how to solve this a^3>-1 and the answer is a<-1 , can anyone explain to me?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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saifoo.khan
  • saifoo.khan
Yea!!
anonymous
  • anonymous
a^3 > -1 a > -1
anonymous
  • anonymous
cube toot of a is?

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More answers

anonymous
  • anonymous
a^3>-1 a>-1
anonymous
  • anonymous
toot !? lol
saifoo.khan
  • saifoo.khan
take cube root on both sides.
saifoo.khan
  • saifoo.khan
the cube root of -1 is -1.
anonymous
  • anonymous
ull end up with -1 again hence the answer
anonymous
  • anonymous
no saif its -1
saifoo.khan
  • saifoo.khan
what nick?
anonymous
  • anonymous
saif said the same
anonymous
  • anonymous
-1^3=-1
saifoo.khan
  • saifoo.khan
Yea!
anonymous
  • anonymous
yes, it's cube root. and i still confuse
anonymous
  • anonymous
or there is another way too a^3 > -1 a^3 +1 > 0 (a + 1)(a^2 + 1 -a)> 0 ^ ^ real complex a >-1
jim_thompson5910
  • jim_thompson5910
a^3 > -1 a^3 + 1 > 0 (a+1)(a^2-a+1) > 0 .. factor with the sum of cubes formula Since a^2-a+1 is ALWAYS positive (look at the graph of a^2-a+1 to see this or complete the square on a^2-a+1), this means that a^2-a+1 has NO influence on the sign of the entire expression. So everything is dependent on the factor a+1 So because the entire expression is positive, and the sign depends on a+1, we know for sure that a+1 > 0 a+1 > 0 a > -1 So the solution is a > -1
anonymous
  • anonymous
but I am sure you don't want the complex thing so just so a>-1
jim_thompson5910
  • jim_thompson5910
make sure that there are no typos
anonymous
  • anonymous
Good Job Jim
anonymous
  • anonymous
okay, thank you all :)

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