how to solve this a^3>-1 and the answer is a<-1 , can anyone explain to me?

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how to solve this a^3>-1 and the answer is a<-1 , can anyone explain to me?

Mathematics
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Yea!!
a^3 > -1 a > -1
cube toot of a is?

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Other answers:

a^3>-1 a>-1
toot !? lol
take cube root on both sides.
the cube root of -1 is -1.
ull end up with -1 again hence the answer
no saif its -1
what nick?
saif said the same
-1^3=-1
Yea!
yes, it's cube root. and i still confuse
or there is another way too a^3 > -1 a^3 +1 > 0 (a + 1)(a^2 + 1 -a)> 0 ^ ^ real complex a >-1
a^3 > -1 a^3 + 1 > 0 (a+1)(a^2-a+1) > 0 .. factor with the sum of cubes formula Since a^2-a+1 is ALWAYS positive (look at the graph of a^2-a+1 to see this or complete the square on a^2-a+1), this means that a^2-a+1 has NO influence on the sign of the entire expression. So everything is dependent on the factor a+1 So because the entire expression is positive, and the sign depends on a+1, we know for sure that a+1 > 0 a+1 > 0 a > -1 So the solution is a > -1
but I am sure you don't want the complex thing so just so a>-1
make sure that there are no typos
Good Job Jim
okay, thank you all :)

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