Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
dinainjune
Group Title
how to solve this a^3>1 and the answer is a<1 , can anyone explain to me?
 2 years ago
 2 years ago
dinainjune Group Title
how to solve this a^3>1 and the answer is a<1 , can anyone explain to me?
 2 years ago
 2 years ago

This Question is Closed

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
a^3 > 1 a > 1
 2 years ago

hahd Group TitleBest ResponseYou've already chosen the best response.0
cube toot of a is?
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.3
a^3>1 a>1
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
toot !? lol
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
take cube root on both sides.
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
the cube root of 1 is 1.
 2 years ago

hahd Group TitleBest ResponseYou've already chosen the best response.0
ull end up with 1 again hence the answer
 2 years ago

Nick_Black Group TitleBest ResponseYou've already chosen the best response.3
no saif its 1
 2 years ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
what nick?
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
saif said the same
 2 years ago

dinainjune Group TitleBest ResponseYou've already chosen the best response.0
yes, it's cube root. and i still confuse
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
or there is another way too a^3 > 1 a^3 +1 > 0 (a + 1)(a^2 + 1 a)> 0 ^ ^ real complex a >1
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
a^3 > 1 a^3 + 1 > 0 (a+1)(a^2a+1) > 0 .. factor with the sum of cubes formula Since a^2a+1 is ALWAYS positive (look at the graph of a^2a+1 to see this or complete the square on a^2a+1), this means that a^2a+1 has NO influence on the sign of the entire expression. So everything is dependent on the factor a+1 So because the entire expression is positive, and the sign depends on a+1, we know for sure that a+1 > 0 a+1 > 0 a > 1 So the solution is a > 1
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
but I am sure you don't want the complex thing so just so a>1
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
make sure that there are no typos
 2 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.0
Good Job Jim
 2 years ago

dinainjune Group TitleBest ResponseYou've already chosen the best response.0
okay, thank you all :)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.