A community for students.
Here's the question you clicked on:
 0 viewing
Mathtrouble12
 4 years ago
What is the domain and range of the quadratic equation y = –2x^2– 32x – 126?
Mathtrouble12
 4 years ago
What is the domain and range of the quadratic equation y = –2x^2– 32x – 126?

This Question is Closed

kushashwa
 4 years ago
Best ResponseYou've already chosen the best response.0y=2x^(2)32x126 Since x is on the righthand side of the equation, switch the sides so it is on the lefthand side of the equation. 2x^(2)32x126=y To set the lefthand side of the equation equal to 0, move all the expressions to the lefthand side. 2x^(2)32xy126=0 Multiply each term in the equation by 1. 2x^(2)*132x*1y*1126*1=0*1 Simplify the lefthand side of the equation by multiplying out all the terms. 2x^(2)+32x+y+126=0*1 Multiply 0 by 1 to get 0. 2x^(2)+32x+y+126=0 Use the quadratic formula to find the solutions. In this case, the values are a=2, b=32, and c=1y. x=(b\~(b^(2)4ac))/(2a) where ax^(2)+bx+c=0 Substitute in the values of a=2, b=32, and c=1y. x=(32\~((32)^(2)4(2)(1y)))/(2(2)) Simplify the section inside the radical. x=(32\2~(2(y128)))/(2(2)) Simplify the denominator of the quadratic formula. x=(32\2~(2(y128)))/(4) First, solve the + portion of \. x=(32+2~(2(y128)))/(4) Simplify the expression to solve for the + portion of the \. x=(16+~(2(y128)))/(2) Next, solve the  portion of \. x=(322~(2(y128)))/(4) Simplify the expression to solve for the  portion of the \. x=(16~(2(y128)))/(2) The final answer is the combination of both solutions. x=(16+~(2(y128)))/(2),(16~(2(y128)))/(2) The domain of an expression is all real numbers except for the regions where the expression is undefined. This can occur where the denominator equals 0, a square root is less than 0, or a logarithm is less than or equal to 0. All of these are undefined and therefore are not part of the domain. (2(y128))<0 Solve the equation to find where the original expression is undefined. y>128 The domain of the rational expression is all real numbers except where the expression is undefined. y<=128_(<Z>I<z>,128] The domain of the inverse of y=2x^(2)32x126 is equal to the range of f(y)=((16+~(2(y128))))/(2). Range: y<=128_(<Z>I<z>,128]

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.1domain: ALL REAL NUMBERS range: FROM SECOND COORDINATE OF VERTEX DOWN vertex is \[\frac{b}{2a}\] in this case you get 8 plug that in, get 2 range is \[(\infty,2]\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.