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anonymous
 4 years ago
The activation energy of a certain reaction is 40.5Kj/mol.the rate constant is Given 0.0130s^1 the initial temperature is 20 C , what would the rate constant be at a temperature of 100 C ?
anonymous
 4 years ago
The activation energy of a certain reaction is 40.5Kj/mol.the rate constant is Given 0.0130s^1 the initial temperature is 20 C , what would the rate constant be at a temperature of 100 C ?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0E=RT ln (k/A) 40.5 = 0.08206(295.15) ln (0.0130/A) e^(40.5/(0.08206(293.15))) = 0.0130/A 0.07000234854... approx = A use A to solve for k at 100C (373.15 K): 40.5=RT ln (k/A) 40.5=0.08206(373.15) ln (k/30/0.07000234854) 40.5/(0.08206(373.15))=ln (k/30/0.07000234854) e^(40.5/(0.08206(373.15)))=k/0.07000234854 k=0.2627397387 pls. double check my calculations :))

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thank let me do so

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think there's an error

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0line 2: 40.5 = 0.08206(293.15) ln (0.0130/A)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im getting a very big answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0last line: 0.01865088557

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the rate constant should be at least close to 0.0130s^1. not geater than 1.
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