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The activation energy of a certain reaction is 40.5Kj/mol.the rate constant is Given 0.0130s^1 the initial temperature is 20 C , what would the rate constant be at a temperature of 100 C ?
 2 years ago
 2 years ago
The activation energy of a certain reaction is 40.5Kj/mol.the rate constant is Given 0.0130s^1 the initial temperature is 20 C , what would the rate constant be at a temperature of 100 C ?
 2 years ago
 2 years ago

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soxhletapparatusBest ResponseYou've already chosen the best response.2
E=RT ln (k/A) 40.5 = 0.08206(295.15) ln (0.0130/A) e^(40.5/(0.08206(293.15))) = 0.0130/A 0.07000234854... approx = A use A to solve for k at 100C (373.15 K): 40.5=RT ln (k/A) 40.5=0.08206(373.15) ln (k/30/0.07000234854) 40.5/(0.08206(373.15))=ln (k/30/0.07000234854) e^(40.5/(0.08206(373.15)))=k/0.07000234854 k=0.2627397387 pls. double check my calculations :))
 2 years ago

eistein+newton+gallileo=_meBest ResponseYou've already chosen the best response.0
ok thank let me do so
 2 years ago

eistein+newton+gallileo=_meBest ResponseYou've already chosen the best response.0
i think there's an error
 2 years ago

soxhletapparatusBest ResponseYou've already chosen the best response.2
line 2: 40.5 = 0.08206(293.15) ln (0.0130/A)
 2 years ago

eistein+newton+gallileo=_meBest ResponseYou've already chosen the best response.0
im getting a very big answer
 2 years ago

soxhletapparatusBest ResponseYou've already chosen the best response.2
last line: 0.01865088557
 2 years ago

soxhletapparatusBest ResponseYou've already chosen the best response.2
the rate constant should be at least close to 0.0130s^1. not geater than 1.
 2 years ago
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