anonymous
  • anonymous
Just need confirmation again (2t^3)^4 + 2t^12?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
It's supposed to be a equals sign!
anonymous
  • anonymous
Sorry.
anonymous
  • anonymous
first you need to apply this rule of exponents to the left side of that equation: (a^m)^n=a^m*n

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anonymous
  • anonymous
if you did that, then you are correct
anonymous
  • anonymous
If the whole thing is raised to the power of 4 as suggested by the () then that would include the 2 in the base as well.. so 2^4 is also necessary
anonymous
  • anonymous
What...? o.o
anonymous
  • anonymous
If the problem has parenthesis then it means each thing in the parenthesis is to use the exponent. You can think of them separately... (2t^3)^4 = [2^4][(t^3)^4]
jim_thompson5910
  • jim_thompson5910
\[\large (2t^3)^4\] \[\large (2t^3)(2t^3)(2t^3)(2t^3)\] \[\large (2*2*2*2)(t^3*t^3*t^3*t^3)\] \[\large 16t^{3+3+3+3}\] \[\large 16t^{12}\] So \[\large (2t^3)^4=16t^{12}\]

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