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Adorkable

  • 4 years ago

Just need confirmation again (2t^3)^4 + 2t^12?

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  1. Adorkable
    • 4 years ago
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    It's supposed to be a equals sign!

  2. Adorkable
    • 4 years ago
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    Sorry.

  3. LagrangeSon678
    • 4 years ago
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    first you need to apply this rule of exponents to the left side of that equation: (a^m)^n=a^m*n

  4. LagrangeSon678
    • 4 years ago
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    if you did that, then you are correct

  5. nicEscott
    • 4 years ago
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    If the whole thing is raised to the power of 4 as suggested by the () then that would include the 2 in the base as well.. so 2^4 is also necessary

  6. Adorkable
    • 4 years ago
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    What...? o.o

  7. nicEscott
    • 4 years ago
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    If the problem has parenthesis then it means each thing in the parenthesis is to use the exponent. You can think of them separately... (2t^3)^4 = [2^4][(t^3)^4]

  8. jim_thompson5910
    • 4 years ago
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    \[\large (2t^3)^4\] \[\large (2t^3)(2t^3)(2t^3)(2t^3)\] \[\large (2*2*2*2)(t^3*t^3*t^3*t^3)\] \[\large 16t^{3+3+3+3}\] \[\large 16t^{12}\] So \[\large (2t^3)^4=16t^{12}\]

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