## mathtard Group Title Solve by completing the square x^2-14x=10 3 years ago 3 years ago

1. LagrangeSon678

take half the coefficent of -14, it should be -7. The we have (x-7)^2 which equals=x^2-14x+49. That means you get: (x-7)^2=59

2. LagrangeSon678

or (x-7)^2-59=0

3. jim_thompson5910

$\large x^2-14x=10$ $\large x^2-14x-10=0$ $\large x^2-14x+49-49-10=0$ $\large (x-7)^2-49-10=0$ $\large (x-7)^2-59=0$ $\large (x-7)^2=59$ $\large x-7=\pm\sqrt{59}$ $\large x=7\pm\sqrt{59}$

4. LagrangeSon678

x=7plus or mius sqrt59

5. satellite73

$x^2-14x=10$ $(x-7)^2=10+7^2=59$ $x-7=\pm\sqrt{59}$ $x=7\pm\sqrt{59}$

6. nilankshi

good