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- anonymous

Show all work. A disc jockey has 10 songs to play. Seven are slow songs, and three are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 10 songs if
The songs can be played in any order.
The first song must be a slow song and the last song must be a slow song.
The first two songs must be fast songs.

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- anonymous

- chestercat

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- anonymous

any order 10!

- anonymous

oops i had slow and fast backwards.

- anonymous

huh!

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- anonymous

i screwed up on #2 not i have to think.

- anonymous

zarkon?

- anonymous

7 for the first, 6 for the last, and 8*7*6*5*4*3 for the middle so i think it is
7*6/8*7*6*5*4*3

- anonymous

How can the first song be both fast and slow?

- anonymous

first two slow
3*2 then 8*7*6*5*4*3

- Zarkon

is there a reason you are dropping the 2?

- Zarkon

\[10!\]
\[_7P_2\cdot 8!\]
\[_3P_2\cdot 8!\]

- anonymous

i have no clue what yall are doing please explain!

- Zarkon

\[_7P_2=7\times 6\]
\[_3P_2=3\times 2\]

- Zarkon

1) 3628800
2) 1693440
3) 241920

- anonymous

ok so it was right yes? i mean what i wrote

- anonymous

oh no it was wrong. i didn't put the 2 at the end. doh

- anonymous

first two slow 3*2 then 8*7*6*5*4*3*2
so
3*2*8*7*6*5*4*3*2

- anonymous

i would like to think that was a typo

- Zarkon

I would too

- anonymous

lol!

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