## keebler01 4 years ago Show all work. A disc jockey has 10 songs to play. Seven are slow songs, and three are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 10 songs if The songs can be played in any order. The first song must be a slow song and the last song must be a slow song. The first two songs must be fast songs.

1. satellite73

any order 10!

2. satellite73

oops i had slow and fast backwards.

3. keebler01

huh!

4. satellite73

i screwed up on #2 not i have to think.

5. satellite73

zarkon?

6. satellite73

7 for the first, 6 for the last, and 8*7*6*5*4*3 for the middle so i think it is 7*6/8*7*6*5*4*3

7. xChessMachinex

How can the first song be both fast and slow?

8. satellite73

first two slow 3*2 then 8*7*6*5*4*3

9. Zarkon

is there a reason you are dropping the 2?

10. Zarkon

$10!$ $_7P_2\cdot 8!$ $_3P_2\cdot 8!$

11. keebler01

i have no clue what yall are doing please explain!

12. Zarkon

$_7P_2=7\times 6$ $_3P_2=3\times 2$

13. Zarkon

1) 3628800 2) 1693440 3) 241920

14. satellite73

ok so it was right yes? i mean what i wrote

15. satellite73

oh no it was wrong. i didn't put the 2 at the end. doh

16. satellite73

first two slow 3*2 then 8*7*6*5*4*3*2 so 3*2*8*7*6*5*4*3*2

17. satellite73

i would like to think that was a typo

18. Zarkon

I would too

19. satellite73

lol!