xavier11
multiplicative inverse of \[1\div3+i\]



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anonymous
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i could have sworn we just did this

xavier11
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nope!

anonymous
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\[\frac{1}{3+i}\]?

anonymous
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multiplicative inverse is
\[3+i\] because if you multiply them together you get 1

xavier11
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nope!

xavier11
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nope!

xavier11
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so the answer is 3+i?

anonymous
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it is true that
\[\frac{1}{3+i}\times (3+i)=1\]

anonymous
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complex numbers are weird, but not that weird

anonymous
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hello joe
hello fred

joemath314159
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i believe you satellite!

Owlfred
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xavier11, it's best when you put work in your questions so you understand how to derive the answer.

xavier11
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nope!

xavier11
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yes i completely agree, im just a little pressed for time right now