Here's the question you clicked on:
rsher2295
2x+3y=3 x-12y=-9 solve for x and y
the answer should be x=1/3,y=7/9
the mistake was leaving a -9 instead of a 3 in the substitution of the first equation...
2x+3y=3 x-12y=-9 make x the subject in the 2nd eqn x=12y-9 put it into the first eqn 2(12y-9)+3y=-9 24y-18+3y=-9 27y-18=-9 27y=-27 y=-1 put y=-1 into 2x+3y=3 2x-3=3 2x=6 x=3 x=3, y=-1