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a123 Group Title

Simplify: (3x^5/6) * (8x^2/3)? Please show steps; I don't understand how to do these types of problems.

  • 2 years ago
  • 2 years ago

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  1. saifoo.khan Group Title
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    |dw:1314147083078:dw|

    • 2 years ago
  2. PetiteJiji Group Title
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    1) Rewrite the question (see the attachment) 2) Multiply all the numbers 3) then x terms the final answer is\[4/3 x ^{7}\]

    • 2 years ago
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  3. Hero Group Title
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    Thought you didn't find the drawing board useful

    • 2 years ago
  4. saifoo.khan Group Title
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    |dw:1314147216669:dw|

    • 2 years ago
  5. Hero Group Title
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    petitejiji, your solution is confusing

    • 2 years ago
  6. Hero Group Title
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    \[\frac{4x^7}{3}\]

    • 2 years ago
  7. saifoo.khan Group Title
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    & wrong too!

    • 2 years ago
  8. PetiteJiji Group Title
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    |dw:1314147278552:dw|

    • 2 years ago
  9. saifoo.khan Group Title
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    is that 100, lol.

    • 2 years ago
  10. jim_thompson5910 Group Title
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    pretty sure (3x^5/6) * (8x^2/3) is really \[\large (3x^{\frac{5}{6}})(8x^{\frac{2}{3}})\] can we get a confirmation?

    • 2 years ago
  11. a123 Group Title
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    Yes to jim_thompson5910, sorry for any confusion.

    • 2 years ago
  12. Hero Group Title
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    I wish people would use parentheses properly

    • 2 years ago
  13. a123 Group Title
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    hero: sorry, I didn't realize it was wrong until I looked at it again.

    • 2 years ago
  14. jim_thompson5910 Group Title
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    multiply the coefficients to get 3*8 = 24, this is the final coefficient now add the exponents: 5/6+2/3 = 5/6+4/6 = 9/6 = 3/2, this is the final exponent So \[\large (3x^{\frac{5}{6}})(8x^{\frac{2}{3}})=24x^{\frac{3}{2}}\]

    • 2 years ago
  15. Hero Group Title
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    a123, if it's wrong, speak up. Don't let confusion linger for too long.

    • 2 years ago
  16. a123 Group Title
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    jim: is that the same thing as \[(\sqrt{24x})^{3}\]

    • 2 years ago
  17. jim_thompson5910 Group Title
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    no because the exponent is only over the x and not the 24; however, you can rewrite it as \[\large 24\sqrt{x^3}\]

    • 2 years ago
  18. jim_thompson5910 Group Title
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    and simplify to get \[\large 24x\sqrt{x}\]

    • 2 years ago
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