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Abe_le_Babe
 3 years ago
How to find Horizontal Asymptote of: (2x+1)/(x2)
Abe_le_Babe
 3 years ago
How to find Horizontal Asymptote of: (2x+1)/(x2)

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101Ryan101
 3 years ago
Best ResponseYou've already chosen the best response.0it's when the function = zero in the numerator... so it's when 2x+1 = 0 for vertical asymptote it's when the function is undefined so when x2 = 0

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0you have the correct way to find the vertical asymptote ryan, but not the horizontal

Abe_le_Babe
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, I know the Vertical, I was inquiring about the Horizontal.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0since the degrees are equal, simply divide the leading coefficients to get 2/1 = 2 So the horizontal asymptote is y = 2

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0If the degree of the denominator is larger, then the horizontal asymptote is simply y = 0

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0If the degree of the numerator is larger, then you have to use polynomial long division (but at this point, you won't have a horizontal asymptote)

Abe_le_Babe
 3 years ago
Best ResponseYou've already chosen the best response.0So, if equal degrees, you just divide it out. If denominator degree is greater, the y asymptote is simply 0. and if the numerator degree is greater, you use long division and have a slant asymptote. Is that correct?

helpingtutors
 3 years ago
Best ResponseYou've already chosen the best response.1you are exactly correct !! Abe!!

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.0that is correct, either a slant asymptote or something a bit more complicated

Abe_le_Babe
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you very much Jim and Star.
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