anonymous
  • anonymous
How to find Horizontal Asymptote of: (2x+1)/(x-2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
it's when the function = zero in the numerator... so it's when 2x+1 = 0 for vertical asymptote it's when the function is undefined so when x-2 = 0
jim_thompson5910
  • jim_thompson5910
you have the correct way to find the vertical asymptote ryan, but not the horizontal
anonymous
  • anonymous
Yes, I know the Vertical, I was inquiring about the Horizontal.

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jim_thompson5910
  • jim_thompson5910
since the degrees are equal, simply divide the leading coefficients to get 2/1 = 2 So the horizontal asymptote is y = 2
jim_thompson5910
  • jim_thompson5910
If the degree of the denominator is larger, then the horizontal asymptote is simply y = 0
jim_thompson5910
  • jim_thompson5910
If the degree of the numerator is larger, then you have to use polynomial long division (but at this point, you won't have a horizontal asymptote)
anonymous
  • anonymous
So, if equal degrees, you just divide it out. If denominator degree is greater, the y asymptote is simply 0. and if the numerator degree is greater, you use long division and have a slant asymptote. Is that correct?
anonymous
  • anonymous
you are exactly correct !! Abe!!
jim_thompson5910
  • jim_thompson5910
that is correct, either a slant asymptote or something a bit more complicated
anonymous
  • anonymous
Thank you very much Jim and Star.

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