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101Ryan101 Group TitleBest ResponseYou've already chosen the best response.0
it's when the function = zero in the numerator... so it's when 2x+1 = 0 for vertical asymptote it's when the function is undefined so when x2 = 0
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
you have the correct way to find the vertical asymptote ryan, but not the horizontal
 2 years ago

Abe_le_Babe Group TitleBest ResponseYou've already chosen the best response.0
Yes, I know the Vertical, I was inquiring about the Horizontal.
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
since the degrees are equal, simply divide the leading coefficients to get 2/1 = 2 So the horizontal asymptote is y = 2
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
If the degree of the denominator is larger, then the horizontal asymptote is simply y = 0
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
If the degree of the numerator is larger, then you have to use polynomial long division (but at this point, you won't have a horizontal asymptote)
 2 years ago

Abe_le_Babe Group TitleBest ResponseYou've already chosen the best response.0
So, if equal degrees, you just divide it out. If denominator degree is greater, the y asymptote is simply 0. and if the numerator degree is greater, you use long division and have a slant asymptote. Is that correct?
 2 years ago

helpingtutors Group TitleBest ResponseYou've already chosen the best response.1
you are exactly correct !! Abe!!
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
that is correct, either a slant asymptote or something a bit more complicated
 2 years ago

Abe_le_Babe Group TitleBest ResponseYou've already chosen the best response.0
Thank you very much Jim and Star.
 2 years ago
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