Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Abe_le_Babe Group Title

How to find Horizontal Asymptote of: (2x+1)/(x-2)

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. 101Ryan101 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    it's when the function = zero in the numerator... so it's when 2x+1 = 0 for vertical asymptote it's when the function is undefined so when x-2 = 0

    • 2 years ago
  2. jim_thompson5910 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    you have the correct way to find the vertical asymptote ryan, but not the horizontal

    • 2 years ago
  3. Abe_le_Babe Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, I know the Vertical, I was inquiring about the Horizontal.

    • 2 years ago
  4. jim_thompson5910 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    since the degrees are equal, simply divide the leading coefficients to get 2/1 = 2 So the horizontal asymptote is y = 2

    • 2 years ago
  5. jim_thompson5910 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    If the degree of the denominator is larger, then the horizontal asymptote is simply y = 0

    • 2 years ago
  6. jim_thompson5910 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    If the degree of the numerator is larger, then you have to use polynomial long division (but at this point, you won't have a horizontal asymptote)

    • 2 years ago
  7. Abe_le_Babe Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    So, if equal degrees, you just divide it out. If denominator degree is greater, the y asymptote is simply 0. and if the numerator degree is greater, you use long division and have a slant asymptote. Is that correct?

    • 2 years ago
  8. helpingtutors Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    you are exactly correct !! Abe!!

    • 2 years ago
  9. jim_thompson5910 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    that is correct, either a slant asymptote or something a bit more complicated

    • 2 years ago
  10. Abe_le_Babe Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you very much Jim and Star.

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.