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find dx/dy for the following equations
1.) y = square root of 3 (x+1)/x1)
 2 years ago
 2 years ago
find dx/dy for the following equations 1.) y = square root of 3 (x+1)/x1)
 2 years ago
 2 years ago

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kushashwa23Best ResponseYou've already chosen the best response.0
let me have a look to this closely
 2 years ago

OwlfredBest ResponseYou've already chosen the best response.0
babz83 is smilbourn your mother?
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
cbrt((x+1)/(x1)) right?
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
change the radical to its proper exponent form [ (x+1)/(x1) ]^(1/3) and work thru
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
this aint gonna be nice with my formatting off
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
lets start with the ^1/3; power rule says bring it down and 1
 2 years ago

babz83Best ResponseYou've already chosen the best response.0
@owlfred...nope remember she said she got an A in calc.... i would not be posting these questions
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
(1/3) [ (x+1)/(x1) ]^(2/3) and out pops the innards for the chain rule
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
Dx(x+1)/(x1) = (x1)(1)  (x+1)(1) // (x1)^2 by quotient rule
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
simplify to: 2x/(x1)^2 right?
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
put it all together to go: 2x/3(x1)^2) [ (x1)/(x+1) ]^(2/3)
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
\[\frac{2x}{3(x1)^2}\left(\frac{x1}{x+1}\right)^{2/3}\]right?
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
ill type it in the latex stuff fo try to make it easier to follow
 2 years ago

babz83Best ResponseYou've already chosen the best response.0
ah i get it thats after removing the cube root
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
\[\sqrt[3]{\frac{x+1}{x1}}\] \[Dx\left(\frac{x+1}{x1}\right)^{1/3}\] \[\frac{1}{3}\left(\frac{x+1}{x1}\right)^{2/3}Dx(\frac{x+1}{x1})\] so far
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
2/3 just flips it all over and goes positive again right?
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
\[\frac{1}{3}\left(\frac{x1}{x+1}\right)^{2/3}Dx(\frac{x+1}{x1})\] \[... Dx(\frac{x+1}{x1})=\frac{bt'b't}{b^2}\] \[... \frac{(x1)(1)(x+1)(1)}{(x1)^2}\] \[... \frac{(x1)+(x+1)}{(x1)^2}\] \[... \frac{x1+x+1}{(x1)^2}\] \[... \frac{2x}{(x1)^2}\]
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
\[\frac{1}{3}\left(\frac{x1}{x+1}\right)^{2/3}\frac{2x}{(x1)^2}\] are all the parts, just simplify as wanted
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
i see a spot i missed; (x1) has a derivative if 1, not 1
 2 years ago

babz83Best ResponseYou've already chosen the best response.0
i see i have a lot of serious reading to do
 2 years ago

amistre64Best ResponseYou've already chosen the best response.1
\[... \frac{(x1)(1)(x+1)(1)}{(x1)^2}\] \[... \frac{x1x1}{(x1)^2}\] \[... \frac{2}{(x1)^2}\] \[\frac{1}{3}\left(\frac{x1}{x+1}\right)^{2/3}\frac{2}{(x1)^2}\] thats proper, or should be better at least :)
 2 years ago
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