A community for students.
Here's the question you clicked on:
 0 viewing
babz83
 3 years ago
find dx/dy for the following equations
1.) y = square root of 3 (x+1)/x1)
babz83
 3 years ago
find dx/dy for the following equations 1.) y = square root of 3 (x+1)/x1)

This Question is Closed

kushashwa23
 3 years ago
Best ResponseYou've already chosen the best response.0let me have a look to this closely

Owlfred
 3 years ago
Best ResponseYou've already chosen the best response.0babz83 is smilbourn your mother?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1cbrt((x+1)/(x1)) right?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1change the radical to its proper exponent form [ (x+1)/(x1) ]^(1/3) and work thru

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1this aint gonna be nice with my formatting off

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1lets start with the ^1/3; power rule says bring it down and 1

babz83
 3 years ago
Best ResponseYou've already chosen the best response.0@owlfred...nope remember she said she got an A in calc.... i would not be posting these questions

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1(1/3) [ (x+1)/(x1) ]^(2/3) and out pops the innards for the chain rule

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1Dx(x+1)/(x1) = (x1)(1)  (x+1)(1) // (x1)^2 by quotient rule

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1simplify to: 2x/(x1)^2 right?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1put it all together to go: 2x/3(x1)^2) [ (x1)/(x+1) ]^(2/3)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{2x}{3(x1)^2}\left(\frac{x1}{x+1}\right)^{2/3}\]right?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1ill type it in the latex stuff fo try to make it easier to follow

babz83
 3 years ago
Best ResponseYou've already chosen the best response.0ah i get it thats after removing the cube root

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt[3]{\frac{x+1}{x1}}\] \[Dx\left(\frac{x+1}{x1}\right)^{1/3}\] \[\frac{1}{3}\left(\frac{x+1}{x1}\right)^{2/3}Dx(\frac{x+1}{x1})\] so far

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.12/3 just flips it all over and goes positive again right?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{3}\left(\frac{x1}{x+1}\right)^{2/3}Dx(\frac{x+1}{x1})\] \[... Dx(\frac{x+1}{x1})=\frac{bt'b't}{b^2}\] \[... \frac{(x1)(1)(x+1)(1)}{(x1)^2}\] \[... \frac{(x1)+(x+1)}{(x1)^2}\] \[... \frac{x1+x+1}{(x1)^2}\] \[... \frac{2x}{(x1)^2}\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{3}\left(\frac{x1}{x+1}\right)^{2/3}\frac{2x}{(x1)^2}\] are all the parts, just simplify as wanted

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1i see a spot i missed; (x1) has a derivative if 1, not 1

babz83
 3 years ago
Best ResponseYou've already chosen the best response.0i see i have a lot of serious reading to do

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1\[... \frac{(x1)(1)(x+1)(1)}{(x1)^2}\] \[... \frac{x1x1}{(x1)^2}\] \[... \frac{2}{(x1)^2}\] \[\frac{1}{3}\left(\frac{x1}{x+1}\right)^{2/3}\frac{2}{(x1)^2}\] thats proper, or should be better at least :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.