anonymous
  • anonymous
Find a volume of a seedless orange with radius 5cm. 523.60cm 1) suppose the peel of the orange is 0.5cm thick.What volume of the orange is eddible? 2)Express the edible part of the orange as a percent of the whole orange.Round your answer to the nearest percent. Could u explain 1) & 2) solving? Thanks.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Is the orange a perfect sphere?
anonymous
  • anonymous
pls help me
anonymous
  • anonymous
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
lol ok, what's the volume of a sphere formula?
anonymous
  • anonymous
v=4TTr3/2
anonymous
  • anonymous
should look like this: v = (4/3)PI(r)^3
anonymous
  • anonymous
now for question 1) , plug in the radius of the orange for r... like this... v = (4/3)PI(5)^3
anonymous
  • anonymous
yes i did that
anonymous
  • anonymous
ok, so if you want to know the portion that is edible, minus the portion that is not edible, namely 0.5... so now use a radius of 4.5cm and you'll have it...
anonymous
  • anonymous
i did 5.0 - 0.5 and got 4.5
anonymous
  • anonymous
cool, so you need to know the volume of the whole orange, and the volume of the edible part to find the percentage.. Please post the two volumes, and then we'll find the percentage that is edible..
anonymous
  • anonymous
volume of the whole orange = 523.60 volume of the edible part = 380.51
anonymous
  • anonymous
volume of edible part = 381.51 i mean
anonymous
  • anonymous
523.6 is the whole and 381.7 is the part of the edible part...
anonymous
  • anonymous
how did you get 380.70?? i know that is the right answer but i keep on getting 381.51
anonymous
  • anonymous
I didn't get 380.70 I got 381.7 anyway, now we ask "what percent of 523.6 is 381.7" that equates to: x(523.6) = 381.7
anonymous
  • anonymous
wait but where is the x coming from?
anonymous
  • anonymous
now dividing both sides gives 0.72899... and moving the decimal to percent.. 72.899% and rounding... 73% of the orange is for eats.. but personally I like the peel!!! lol
anonymous
  • anonymous
your a genius!!
anonymous
  • anonymous
oh, the x is "what percent" "what percent" is x of (means times) is means (equals) what percent of bla1 = bla2 x times bla1 = bla2 x(bla1) = bla2 x = bla2/bla1
anonymous
  • anonymous
ohhhh. hehe i personally like the of the orange. (:
anonymous
  • anonymous
You'll get it.. learn to turn what you can say into algebra expressions. It gets easy with practice just like speaking! :)
anonymous
  • anonymous
but hard at first..
anonymous
  • anonymous
ok. well thanks.
anonymous
  • anonymous
np

Looking for something else?

Not the answer you are looking for? Search for more explanations.