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starfish33

  • 4 years ago

If G(x) = 3x + 1, then G-1(1) is

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  1. anonymous
    • 4 years ago
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    \[1=3x+1\] \[0=3x\] \[x=0\]

  2. anonymous
    • 4 years ago
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    so \[G(0)=1\] and \[G^{-1}(1)=0\]

  3. starfish33
    • 4 years ago
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    can it be 1/3

  4. anonymous
    • 4 years ago
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    no assuming what you mean is \[G^{-1}(x)\] in inverse function

  5. starfish33
    • 4 years ago
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    Thanks!

  6. anonymous
    • 4 years ago
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    yw

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