starfish33
If G(x) = 3x + 1, then G1(1) is



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anonymous
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\[1=3x+1\]
\[0=3x\]
\[x=0\]

anonymous
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so
\[G(0)=1\] and
\[G^{1}(1)=0\]

starfish33
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can it be 1/3

anonymous
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no assuming what you mean is
\[G^{1}(x)\] in inverse function

starfish33
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Thanks!

anonymous
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yw