Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
raheen
Group Title
With the help of gauss theorem find the stream of the vector field W=[x^2/9.y^2/9,z^2/9] through the part of the cone surface x^2+y^2=2z closed by the deck z=3.
 2 years ago
 2 years ago
raheen Group Title
With the help of gauss theorem find the stream of the vector field W=[x^2/9.y^2/9,z^2/9] through the part of the cone surface x^2+y^2=2z closed by the deck z=3.
 2 years ago
 2 years ago

This Question is Closed

mathandphysics Group TitleBest ResponseYou've already chosen the best response.0
gauss' theorem has to do with electrodynamics flux's. specify which theorem you are asking to use plz
 2 years ago

raheen Group TitleBest ResponseYou've already chosen the best response.0
the convergance theorem
 2 years ago

mathandphysics Group TitleBest ResponseYou've already chosen the best response.0
i don't think gauss has a convergence theorem. not that a know of. he has a divergence theorem but it can't be used here.
 2 years ago

raheen Group TitleBest ResponseYou've already chosen the best response.0
yes it's the divergence theorem
 2 years ago

mathandphysics Group TitleBest ResponseYou've already chosen the best response.0
you're looking for stream, check physics forum?
 2 years ago

NoxiPro Group TitleBest ResponseYou've already chosen the best response.0
just do del dot W DV ∂(M)/∂x+∂(N)/∂y+∂(P)/∂z DV I would use sperical coordinates for this one its a triple integral looks like a lot of work but can be done. see "Stream" flow flux should all have the same meaning, saying that this feild is "FLOWING" through the cone.
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.