A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
jamiemm
 3 years ago
fine the limit if it exists:
lim of x>0 [[1/(3+x)]  (1/3)]/x
jamiemm
 3 years ago
fine the limit if it exists: lim of x>0 [[1/(3+x)]  (1/3)]/x

This Question is Closed

101Ryan101
 3 years ago
Best ResponseYou've already chosen the best response.0(1/9) is what I got taking the derivative to the top and bottom after some algebra..

fiddlearound
 3 years ago
Best ResponseYou've already chosen the best response.1it is 1/9 http://www.wolframalpha.com/input/?i=lim+of+x%3E0+[[1%2F%283%2Bx%29]++%281%2F3%29]%2Fx And click "show steps"

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1this is the derivative of \[f(x)=\frac{1}{x}\] at x = 3 but we can do it without the derivative, just with some algebra

fiddlearound
 3 years ago
Best ResponseYou've already chosen the best response.1hhmmmm. the link gets broken. you'll need to copy/paste it .

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{3+x}\frac{1}{3}=\frac{3(3+x)}{x(3+x)}\] \[=\frac{x}{3(3+x)}\] divide by x get \[\frac{1}{3(3+x)}\] replace x by 0 get \[\frac{1}{9}\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.