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jamiemm
Group Title
fine the limit if it exists:
lim of x>0 [[1/(3+x)]  (1/3)]/x
 3 years ago
 3 years ago
jamiemm Group Title
fine the limit if it exists: lim of x>0 [[1/(3+x)]  (1/3)]/x
 3 years ago
 3 years ago

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101Ryan101 Group TitleBest ResponseYou've already chosen the best response.0
(1/9) is what I got taking the derivative to the top and bottom after some algebra..
 3 years ago

101Ryan101 Group TitleBest ResponseYou've already chosen the best response.0
anyone else?
 3 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
that is right
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
it is 1/9 http://www.wolframalpha.com/input/?i=lim+of+x%3E0+[[1%2F%283%2Bx%29]++%281%2F3%29]%2Fx And click "show steps"
 3 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
this is the derivative of \[f(x)=\frac{1}{x}\] at x = 3 but we can do it without the derivative, just with some algebra
 3 years ago

fiddlearound Group TitleBest ResponseYou've already chosen the best response.1
hhmmmm. the link gets broken. you'll need to copy/paste it .
 3 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{1}{3+x}\frac{1}{3}=\frac{3(3+x)}{x(3+x)}\] \[=\frac{x}{3(3+x)}\] divide by x get \[\frac{1}{3(3+x)}\] replace x by 0 get \[\frac{1}{9}\]
 3 years ago
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