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mathtard
Give exact and approximate solutions to three decimal places. (x+7)^2=36
take square root of both sides then subtract 7 on both sides
and don't forget to write both \[x+7=6\] or \[x+7=-6\]
id +- a sqrt(36) then subtract out a 7
that's easy for you to say
\[(\pm \sqrt{36}-7+7)^2 = 36\]