Here's the question you clicked on:
mathtard
Determine the nature of solutions of the equation x^2-3x+8=0
you need to check the discriminant - know what that is ?
are you familiar with the quadratic equation ?
use quadratic formula
ever seen this formula ? \[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
\[(-b \pm \sqrt{b^{2}-4ac})/2a\]
In general: ax^2+bx+c=0 In your case: a=1 (the coefficient of x^2) b=-3 (coefficient of x) c=8 Use these values and plug them into the discriminant (the thingy inside the square root). \[\Delta=b^2-4ac\] If the discriminant = 0, there is one real solution If the discriminant > 0, there are two real solutions If the discriminant < 0, there are no real solutions