## anonymous 5 years ago Determine the nature of solutions of the equation x^2-3x+8=0

1. anonymous

you need to check the discriminant - know what that is ?

2. anonymous

no

3. anonymous

are you familiar with the quadratic equation ?

4. anonymous

5. anonymous

no not at all.

6. anonymous

ever seen this formula ? $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

7. anonymous
8. anonymous

$(-b \pm \sqrt{b^{2}-4ac})/2a$

9. anonymous

In general: ax^2+bx+c=0 In your case: a=1 (the coefficient of x^2) b=-3 (coefficient of x) c=8 Use these values and plug them into the discriminant (the thingy inside the square root). $\Delta=b^2-4ac$ If the discriminant = 0, there is one real solution If the discriminant > 0, there are two real solutions If the discriminant < 0, there are no real solutions