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quincyd12

  • 4 years ago

a2-5a=50

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  1. a123
    • 4 years ago
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    i assume you mean \[a^2?\]

  2. quincyd12
    • 4 years ago
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    yes

  3. a123
    • 4 years ago
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    in which case: \[a^2 - 5a - 50 = 0\] \[a^2 + 5a - 10a - 50 = 0\] \[a(a + 5) - 10 (a + 5) = 0\] \[(a - 10)(a+5) = 0\]

  4. a123
    • 4 years ago
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    i'm assuming that is what your teacher wanted

  5. quincyd12
    • 4 years ago
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    whats the solution

  6. quincyd12
    • 4 years ago
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    of a

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