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Is there anyone here that can give me detailed help I have some questions that I just can't seem to get right.

Mathematics
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whats the q
Find the vertex, line of symmetry, and the minimum or maximum value. f(x)=8-x^2
yeah, specific questions help out

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Other answers:

I really just need the vertex.
yea if I could get anyone one here to answer my questions.
it straddles the y axis, 8 above origin
-x^2 is a turned over bowl so its max is its vertex y part
and the symmetry is the y axis since it never leaves its home
soup spilled out
3 beans soup all over my lap; just great
so the coordinates for the vertex are (2,8) ?
vertex is \[-\frac{b}{2a}\] for the first coordinate. in this case you might want to write \[f(x)=-x^2+8\] so b = 0 and the vertex is (0,8)
Ah!
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i keep forgettin we got a draw lol
LOL! THANK YOU!!!!
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yikes mine are the worst! that is supposed to be \[y=x^2\] \[y=-x^2\] \[y=-x^2+8\]
amistre picture nice and smooth... like gary coleman
ive got an anti parkinsons device on my mouse ;)

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