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mathtard

  • 4 years ago

Is there anyone here that can give me detailed help I have some questions that I just can't seem to get right.

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  1. mathballet8888
    • 4 years ago
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    whats the q

  2. mathtard
    • 4 years ago
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    Find the vertex, line of symmetry, and the minimum or maximum value. f(x)=8-x^2

  3. amistre64
    • 4 years ago
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    yeah, specific questions help out

  4. mathtard
    • 4 years ago
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    I really just need the vertex.

  5. mathtard
    • 4 years ago
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    yea if I could get anyone one here to answer my questions.

  6. amistre64
    • 4 years ago
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    it straddles the y axis, 8 above origin

  7. amistre64
    • 4 years ago
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    -x^2 is a turned over bowl so its max is its vertex y part

  8. amistre64
    • 4 years ago
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    and the symmetry is the y axis since it never leaves its home

  9. anonymous
    • 4 years ago
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    soup spilled out

  10. amistre64
    • 4 years ago
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    3 beans soup all over my lap; just great

  11. mathtard
    • 4 years ago
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    so the coordinates for the vertex are (2,8) ?

  12. anonymous
    • 4 years ago
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    vertex is \[-\frac{b}{2a}\] for the first coordinate. in this case you might want to write \[f(x)=-x^2+8\] so b = 0 and the vertex is (0,8)

  13. mathtard
    • 4 years ago
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    Ah!

  14. amistre64
    • 4 years ago
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    |dw:1314672133571:dw|

  15. amistre64
    • 4 years ago
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    i keep forgettin we got a draw lol

  16. mathtard
    • 4 years ago
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    LOL! THANK YOU!!!!

  17. anonymous
    • 4 years ago
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    |dw:1314672137462:dw|

  18. anonymous
    • 4 years ago
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    yikes mine are the worst! that is supposed to be \[y=x^2\] \[y=-x^2\] \[y=-x^2+8\]

  19. anonymous
    • 4 years ago
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    amistre picture nice and smooth... like gary coleman

  20. amistre64
    • 4 years ago
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    ive got an anti parkinsons device on my mouse ;)

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