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mathtard Group Title

Find the vertex f(x)= 3x^2-18x+3 please help me. Awards will be given

  • 3 years ago
  • 3 years ago

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  1. satellite73 Group Title
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    use the all mighty formula \[x= -\frac{b}{2a}\] to find the first coordinate

    • 3 years ago
  2. satellite73 Group Title
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    in this case \[a=3,b=-18\] so \[-\frac{b}{2a}=-\frac{-18}{2\times3}=3\]

    • 3 years ago
  3. satellite73 Group Title
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    that is the first coordinate and the second coordinate is what you get when you replace x by 3. you get \[3\times 3^2-18\times 3+3=27-54+3=-27+3=-24\] check my arithmetic because it is late

    • 3 years ago
  4. satellite73 Group Title
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    also because i didn't really compute. as soon as i saw 27 i knew the next one would be -54. always works that way

    • 3 years ago
  5. satellite73 Group Title
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    vertex is (3,-24) unless i messed up

    • 3 years ago
  6. mathtard Group Title
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    so (3,-24) ? and that would make it a maximum right?

    • 3 years ago
  7. satellite73 Group Title
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    heck no

    • 3 years ago
  8. satellite73 Group Title
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    this is a parabola that faces up. no max, but a min

    • 3 years ago
  9. satellite73 Group Title
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    |dw:1314675140476:dw|

    • 3 years ago
  10. satellite73 Group Title
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    the minimum value is -24

    • 3 years ago
  11. mathtard Group Title
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    Ah I got it mixed up!

    • 3 years ago
  12. mathtard Group Title
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    I always do that with the minimum maximum.

    • 3 years ago
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