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mathtard
Group Title
Find the vertex
f(x)= 3x^218x+3
please help me. Awards will be given
 2 years ago
 2 years ago
mathtard Group Title
Find the vertex f(x)= 3x^218x+3 please help me. Awards will be given
 2 years ago
 2 years ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
use the all mighty formula \[x= \frac{b}{2a}\] to find the first coordinate
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
in this case \[a=3,b=18\] so \[\frac{b}{2a}=\frac{18}{2\times3}=3\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
that is the first coordinate and the second coordinate is what you get when you replace x by 3. you get \[3\times 3^218\times 3+3=2754+3=27+3=24\] check my arithmetic because it is late
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
also because i didn't really compute. as soon as i saw 27 i knew the next one would be 54. always works that way
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
vertex is (3,24) unless i messed up
 2 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
so (3,24) ? and that would make it a maximum right?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
heck no
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
this is a parabola that faces up. no max, but a min
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
dw:1314675140476:dw
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
the minimum value is 24
 2 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
Ah I got it mixed up!
 2 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
I always do that with the minimum maximum.
 2 years ago
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