aditya.sinha
integration of ln(sinx) ?



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aditya.sinha
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\[\int\limits_{}^{}\ln(sinx)\]

Ishaan94
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You must remember the by parts rule right?

aditya.sinha
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yes i know.

Ishaan94
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1*ln(sinx)

Ishaan94
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Take 1 as the function to integrate and ln(sinx) to differentiate

aditya.sinha
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\[\int\limits_{}^{}u.v=u \int\limits_{}^{}v\int\limits_{}^{}(du/dx.\int\limits_{}^{}vdx)\]

aditya.sinha
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is it right ?

Ishaan94
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ah Yes it is
U = ln sinx
V =1

aditya.sinha
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i got stuck up at \[x \ln sinx.\int\limits_{}^{}xcos x dx/sinx\] i cant make substitution of sinx =t as x remains there

Ishaan94
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okay
use by parts after substitution again

Ishaan94
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\[x = sin^{1}t\]

aditya.sinha
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trying ...

aditya.sinha
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\[x=\sin^{1} t \] didnt work well ..it gets me more to intgrate

Ishaan94
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yup okay I have to try it on my notebook

aditya.sinha
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thank you very much . sensei


Ishaan94
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ah I didn't get much ahead but see the integral scroll down a little

aditya.sinha
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This one was pretty tough. wondering why these questions are given to IIT aspirants

Ishaan94
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lol

Ishaan94
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Yea I know did you solve quadratic for IIT

Ishaan94
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ah I still can't figure out how am I supposed to do them in 2 minutes I have posted a question go to my profile you will see

Ishaan94
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question is quadratic related
