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\[2x/(x+3) + 5/x - 4 = 18/x(x+3)\]

multiply both sides by x+3
and also x
to get rid of the denominators

i did that and it didn't work. can you do it out in steps then?

\[x(x+3)\frac{2x}{x+3}+x(x+3)\frac{5}{x}-4x(x+3)=x(x+3)\frac{18}{x(x+3)}\]

\[x(2x)+(x+3)(5)-4x(x+3)=18\]

THANK YOU. How do you do fractions in the equation editor??? :o)

distribute and combine like terms
put in the form
ax^2+bx+c=0
and use the quadratic formula

frac{x(x+3)}{16}