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a123

  • 4 years ago

Can you explain this with steps? (problem coming in the equation editor)

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  1. a123
    • 4 years ago
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    \[2x/(x+3) + 5/x - 4 = 18/x(x+3)\]

  2. myininaya
    • 4 years ago
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    multiply both sides by x+3 and also x to get rid of the denominators

  3. a123
    • 4 years ago
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    i did that and it didn't work. can you do it out in steps then?

  4. myininaya
    • 4 years ago
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    \[x(x+3)\frac{2x}{x+3}+x(x+3)\frac{5}{x}-4x(x+3)=x(x+3)\frac{18}{x(x+3)}\]

  5. myininaya
    • 4 years ago
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    \[x(2x)+(x+3)(5)-4x(x+3)=18\]

  6. a123
    • 4 years ago
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    THANK YOU. How do you do fractions in the equation editor??? :o)

  7. myininaya
    • 4 years ago
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    distribute and combine like terms put in the form ax^2+bx+c=0 and use the quadratic formula

  8. myininaya
    • 4 years ago
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    frac{x(x+3)}{16}

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