## a123 Group Title Can you explain this with steps? (problem coming in the equation editor) 3 years ago 3 years ago

1. a123

$2x/(x+3) + 5/x - 4 = 18/x(x+3)$

2. myininaya

multiply both sides by x+3 and also x to get rid of the denominators

3. a123

i did that and it didn't work. can you do it out in steps then?

4. myininaya

$x(x+3)\frac{2x}{x+3}+x(x+3)\frac{5}{x}-4x(x+3)=x(x+3)\frac{18}{x(x+3)}$

5. myininaya

$x(2x)+(x+3)(5)-4x(x+3)=18$

6. a123

THANK YOU. How do you do fractions in the equation editor??? :o)

7. myininaya

distribute and combine like terms put in the form ax^2+bx+c=0 and use the quadratic formula

8. myininaya

frac{x(x+3)}{16}