anonymous
  • anonymous
Can you explain this with steps? (problem coming in the equation editor)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[2x/(x+3) + 5/x - 4 = 18/x(x+3)\]
myininaya
  • myininaya
multiply both sides by x+3 and also x to get rid of the denominators
anonymous
  • anonymous
i did that and it didn't work. can you do it out in steps then?

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myininaya
  • myininaya
\[x(x+3)\frac{2x}{x+3}+x(x+3)\frac{5}{x}-4x(x+3)=x(x+3)\frac{18}{x(x+3)}\]
myininaya
  • myininaya
\[x(2x)+(x+3)(5)-4x(x+3)=18\]
anonymous
  • anonymous
THANK YOU. How do you do fractions in the equation editor??? :o)
myininaya
  • myininaya
distribute and combine like terms put in the form ax^2+bx+c=0 and use the quadratic formula
myininaya
  • myininaya
frac{x(x+3)}{16}

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