anonymous
  • anonymous
When we say \[\frac{\mathrm{d} y}{\mathrm{d} x}\], it also be written as \[\Delta x\] or \[\Delta y\]?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
not the same thing
anonymous
  • anonymous
no thats different dy/dx is a derivatice delta y and delta x are changes
anonymous
  • anonymous
Isn't the derivative the change? Like for dy/dx, it is the change in the y-axis for each x value? When what are delta x and delta y?

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anonymous
  • anonymous
the derivative can be written (in fact historically was almost always written) as \[\lim_{\Delta x \rightarrow 0}\frac{\Delta y}{\Delta x}\]
amistre64
  • amistre64
put your hands 14 inches apart; \(\Delta\)x = 14 inches; as you bring your hands together that \(\Delta\)x gets smaller and smaller. The moment your hands touch and the distance is gone; you have reached dx
amistre64
  • amistre64
the ghost of a departed value
anonymous
  • anonymous
but notice it is a limit that gives you \[\frac{dy}{dx}\]as you take the limit, the greek letter becomes an english letter
amistre64
  • amistre64
god save the queen!!
anonymous
  • anonymous
sort of like \[\sum\] and \[\int\]
anonymous
  • anonymous
who you calling a queen?
amistre64
  • amistre64
♫♫...we are the champions .... ♫♫
anonymous
  • anonymous
oh of course.
amistre64
  • amistre64
what is the area of a circumference?
anonymous
  • anonymous
So the delta x is the change in the x value, while the dy/dx is the rate of change, the gradient. Since the gradient is the rate of change, I remember the gradient is a function that tells the increase in the y-axis for every increment of x value on the x-axis, is this right? Then this gradient tells a change in the y-axis for each increment of x value, is delta y or delta x?

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