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bookymb143

  • 3 years ago

3*2*6

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  1. brandon376
    • 3 years ago
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    Doesn't really matter what order you multiply them in. 6*6 12*3 18*2 Still get 36.

  2. bookymb143
    • 3 years ago
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    oops rone question

  3. bookymb143
    • 3 years ago
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    it do matter

  4. brandon376
    • 3 years ago
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    ? Is it not multiplication?

  5. bookymb143
    • 3 years ago
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    so but u have to follow the rules bow

  6. REMAINDER
    • 3 years ago
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    3*12 =36

  7. bookymb143
    • 3 years ago
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    no rone answer

  8. satellite73
    • 3 years ago
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    the rules state that \[(a\times b)\times c=a\times (b\times c)\] so no it doesn't matter

  9. bookymb143
    • 3 years ago
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    3*2*6 u have to keep bringing it down

  10. bookymb143
    • 3 years ago
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    i know wat im talking aabout

  11. bookymb143
    • 3 years ago
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    man next question

  12. brandon376
    • 3 years ago
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    Is it\[(3)(2)(6)\]or\[3^{2^{6}}\]

  13. brandon376
    • 3 years ago
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    I am confused.

  14. satellite73
    • 3 years ago
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    qu'est-ce que ça veut dire "rone"?

  15. bookymb143
    • 3 years ago
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    incorrect

  16. REMAINDER
    • 3 years ago
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    3*2 =6 =6*6 =36

  17. satellite73
    • 3 years ago
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    bring it down!

  18. bookymb143
    • 3 years ago
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    yes

  19. bookymb143
    • 3 years ago
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    like

  20. satellite73
    • 3 years ago
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    down the shore?

  21. bookymb143
    • 3 years ago
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    2*2*6 4*6 24

  22. bookymb143
    • 3 years ago
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    there the answer

  23. lmb0ard
    • 3 years ago
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    at the top you put 3*2*6 there you used 2*2*6

  24. bookymb143
    • 3 years ago
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    u people r confusing me

  25. satellite73
    • 3 years ago
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    but you asked 3*2*6

  26. bookymb143
    • 3 years ago
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    i know

  27. brandon376
    • 3 years ago
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    I think you typed your question in wrong booky

  28. bookymb143
    • 3 years ago
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    i was showing an example

  29. bookymb143
    • 3 years ago
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    bye i have to go now i have detention i cant be on the computer bye good day sir

  30. bookymb143
    • 3 years ago
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    btw yal cant understand my work i will post anthor problem

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