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Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.2
dw:1315046753935:dw
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.2
prove that angle d = 90 + (1/2)( angle A)
 3 years ago

sritama Group TitleBest ResponseYou've already chosen the best response.0
ok,in triangle ABC, <ABC+<ACB+<BAC=180 or,<ABC+<ACB=180<BAC <BAC=<A <CDB=<D in, DBC, <DBC+<BCD+<CDB=180 or, <ABC/2+<ACB/2+<CDB=180 or, (<ABC+<ACB)/2+<CDB=180 or, (180<A)+<D=180 or, 90<A/2+<D=180 or, <D=90+<A/2 ( proved )
 3 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
sri used substitution to solve 2 eqs. we could also use elimination. Let y= angle CBD, and x= angle BCD 2y + 2x + A = 180 y + x + D = 180 multiply the first eq by 1/2 and add the 2 eqs then solve for D
 3 years ago

Arnab09 Group TitleBest ResponseYou've already chosen the best response.0
angle<D=180(<DBC+<DCB)=180(<ABC+<ACB)/2=180(180<A)/2=18090+<A/2=90+<A/2
 3 years ago
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