anonymous
  • anonymous
a mass of ikg is attached to a spring produce an extension of 0.1cm. its spring constant is 100N/m 10N/m 1000N/m 1N/m
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
f=-kx f=kx k=f/x k=(1*10)/(0.1*10^-2)= 10,000 N/m but this choice is not availble
anonymous
  • anonymous
IS it 1 kg?
anonymous
  • anonymous
no its answer is 100

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anonymous
  • anonymous
From which book are you asking this question? and secondly which combination are you studying in F.Sc.
anonymous
  • anonymous
first year book of fsc
anonymous
  • anonymous
which page?
anonymous
  • anonymous
are you premed or pre-engr?
anonymous
  • anonymous
i m prepare entry test this question is book kips
anonymous
  • anonymous
i m premed
anonymous
  • anonymous
i get it .......you are on the chapter from oscillations?
anonymous
  • anonymous
yes
anonymous
  • anonymous
the mass is 1 kg..... g=10m/s^2......so the external force acting on the spring is 10 newton
anonymous
  • anonymous
the extention in the string is 0.1cm=0.1*10^-2
anonymous
  • anonymous
divide the first by the second what do you get in N/m?
anonymous
  • anonymous
10/(0.1*10-2) = 10*100*10=10000 N/m definitely......unofficial entry test book not issued by testing authority can have lots of errors....
anonymous
  • anonymous
f=mg=kx 0.1cm=.001m 1kg*10m/s^2=k*0.001m 10N/.001m=10000N/m
anonymous
  • anonymous
The above options are incorrect because. 1kg*10m^s2=! 1000N/m*.001m or 100N/m *.001m and etc

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