zainabrehman
a mass of ikg is attached to a spring produce an extension of 0.1cm. its spring constant is
100N/m
10N/m
1000N/m
1N/m



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mujtabazarrar
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f=kx
f=kx
k=f/x
k=(1*10)/(0.1*10^2)= 10,000 N/m
but this choice is not availble

mujtabazarrar
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IS it 1 kg?

zainabrehman
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no its answer is 100

mujtabazarrar
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From which book are you asking this question? and secondly which combination are you studying in F.Sc.

zainabrehman
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first year book of fsc

mujtabazarrar
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which page?

mujtabazarrar
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are you premed or preengr?

zainabrehman
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i m prepare entry test
this question is book kips

zainabrehman
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i m premed

mujtabazarrar
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i get it .......you are on the chapter from oscillations?

zainabrehman
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yes

mujtabazarrar
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the mass is 1 kg..... g=10m/s^2......so the external force acting on the spring is 10 newton

mujtabazarrar
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the extention in the string is 0.1cm=0.1*10^2

mujtabazarrar
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divide the first by the second what do you get in N/m?

mujtabazarrar
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10/(0.1*102) = 10*100*10=10000 N/m definitely......unofficial entry test book not issued by testing authority can have lots of errors....

JohnLight
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f=mg=kx
0.1cm=.001m
1kg*10m/s^2=k*0.001m
10N/.001m=10000N/m

JohnLight
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The above options are incorrect because.
1kg*10m^s2=! 1000N/m*.001m or 100N/m *.001m and etc