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zainabrehman

  • 4 years ago

a mass of ikg is attached to a spring produce an extension of 0.1cm. its spring constant is 100N/m 10N/m 1000N/m 1N/m

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  1. mujtabazarrar
    • 4 years ago
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    f=-kx f=kx k=f/x k=(1*10)/(0.1*10^-2)= 10,000 N/m but this choice is not availble

  2. mujtabazarrar
    • 4 years ago
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    IS it 1 kg?

  3. zainabrehman
    • 4 years ago
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    no its answer is 100

  4. mujtabazarrar
    • 4 years ago
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    From which book are you asking this question? and secondly which combination are you studying in F.Sc.

  5. zainabrehman
    • 4 years ago
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    first year book of fsc

  6. mujtabazarrar
    • 4 years ago
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    which page?

  7. mujtabazarrar
    • 4 years ago
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    are you premed or pre-engr?

  8. zainabrehman
    • 4 years ago
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    i m prepare entry test this question is book kips

  9. zainabrehman
    • 4 years ago
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    i m premed

  10. mujtabazarrar
    • 4 years ago
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    i get it .......you are on the chapter from oscillations?

  11. zainabrehman
    • 4 years ago
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    yes

  12. mujtabazarrar
    • 4 years ago
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    the mass is 1 kg..... g=10m/s^2......so the external force acting on the spring is 10 newton

  13. mujtabazarrar
    • 4 years ago
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    the extention in the string is 0.1cm=0.1*10^-2

  14. mujtabazarrar
    • 4 years ago
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    divide the first by the second what do you get in N/m?

  15. mujtabazarrar
    • 4 years ago
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    10/(0.1*10-2) = 10*100*10=10000 N/m definitely......unofficial entry test book not issued by testing authority can have lots of errors....

  16. JohnLight
    • 4 years ago
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    f=mg=kx 0.1cm=.001m 1kg*10m/s^2=k*0.001m 10N/.001m=10000N/m

  17. JohnLight
    • 4 years ago
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    The above options are incorrect because. 1kg*10m^s2=! 1000N/m*.001m or 100N/m *.001m and etc

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