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zainabrehman

  • 4 years ago

a simple pendulum is 50cm long its frequency of vibration on the surface of the earth is 1hz 0.5hz 0.7 0.65

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  1. mujtabazarrar
    • 4 years ago
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    0.7 is answer....

  2. mujtabazarrar
    • 4 years ago
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    T=2*pi*squareroot(length/g) , T=2*3.14159*squareroot(50*10^-2/9.8)= 1.42s , f=1/T=1/1.42=0.7Hz

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