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zainabrehman

  • 3 years ago

a body of mass 2 kg is suspended in an elevator by means of a spring balance the balance reads its weight when elevator moves up with an acceleration of 5ms_2 as 30.5n b 29.6n c 26.5n d 9.8n

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  1. mujtabazarrar
    • 3 years ago
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    this question is a bit lengthy....

  2. mujtabazarrar
    • 3 years ago
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    the actual weight of the mass is 20 newtons......first of all..

  3. mujtabazarrar
    • 3 years ago
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    when the elevator moves upward with an acceleration a = 5 m/s^2 ......then the spring balance will show(give reading) of apparent weight more than the actual weight ..... which means that the choice "d"----9.8 is definitely wrong....

  4. mujtabazarrar
    • 3 years ago
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    now while the elevator is moving upward with an acceleration ...... there are two forces acting on it ......the upward tension "T" and downward weight "w".....

  5. mujtabazarrar
    • 3 years ago
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    As the mass "m" along with the elevator are accelerating upward with acceleration "a".....So a net force F=ma is acting in the upward direction ..... this net force F=ma= the difference between T and w. T>W because the elevator+mass are both accelerating upward.

  6. mujtabazarrar
    • 3 years ago
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    Therefore, F=ma=T-W || ma=T-W Putting values|| ma=T-mg|| T=ma+mg|| T=m(a+g)|| T=2(5+9.8)|| T=29.6N As the tension is equal to the apparent weight of the mass being shown by the spring balance....

  7. mujtabazarrar
    • 3 years ago
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    So option b is the right choice....

  8. mujtabazarrar
    • 3 years ago
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