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anonymous
 5 years ago
a body of mass 2 kg is suspended in an elevator by means of a spring balance the balance reads its weight when elevator moves up with an acceleration of 5ms_2 as
30.5n b 29.6n c 26.5n d 9.8n
anonymous
 5 years ago
a body of mass 2 kg is suspended in an elevator by means of a spring balance the balance reads its weight when elevator moves up with an acceleration of 5ms_2 as 30.5n b 29.6n c 26.5n d 9.8n

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this question is a bit lengthy....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the actual weight of the mass is 20 newtons......first of all..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when the elevator moves upward with an acceleration a = 5 m/s^2 ......then the spring balance will show(give reading) of apparent weight more than the actual weight ..... which means that the choice "d"9.8 is definitely wrong....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now while the elevator is moving upward with an acceleration ...... there are two forces acting on it ......the upward tension "T" and downward weight "w".....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0As the mass "m" along with the elevator are accelerating upward with acceleration "a".....So a net force F=ma is acting in the upward direction ..... this net force F=ma= the difference between T and w. T>W because the elevator+mass are both accelerating upward.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Therefore, F=ma=TW  ma=TW Putting values ma=Tmg T=ma+mg T=m(a+g) T=2(5+9.8) T=29.6N As the tension is equal to the apparent weight of the mass being shown by the spring balance....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So option b is the right choice....
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