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Is the answer for 1J1k correct in the solution sheet?
It says \[6 tan(3x)sec^2(3x) = 6sin(x)/ cos^3(x)\] and I don't really get that last step. I'm probably missing something.
 2 years ago
 2 years ago
Is the answer for 1J1k correct in the solution sheet? It says \[6 tan(3x)sec^2(3x) = 6sin(x)/ cos^3(x)\] and I don't really get that last step. I'm probably missing something.
 2 years ago
 2 years ago

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FabianMontescuBest ResponseYou've already chosen the best response.0
I'd expect the answer to be \[6sin(3x)/cos^3(3x)\]
 2 years ago

ThroolBest ResponseYou've already chosen the best response.1
I got the same answer you did  I'm guessing it's a typo
 2 years ago
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