Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
find the integral of 1/root(x^2 + 6x  8)
with explanations
 2 years ago
 2 years ago
find the integral of 1/root(x^2 + 6x  8) with explanations
 2 years ago
 2 years ago

This Question is Closed

LagrangeSon678Best ResponseYou've already chosen the best response.0
thats the integral?
 2 years ago

Izzy25Best ResponseYou've already chosen the best response.0
i got the information from here: :/ idk tho http://mathforum.org/library/drmath/view/64571.html
 2 years ago

nikvistBest ResponseYou've already chosen the best response.1
\[\int\frac{1}{\sqrt{x^2+6x8}}dx=\int\frac{1}{\sqrt{x^2+6x9+1}}dx=\int\frac{1}{\sqrt{1(x3)^2}}dx=\] \[=\arcsin{(x3)}+C\]
 2 years ago

eistein+newton+gallileo=_meBest ResponseYou've already chosen the best response.0
no the answer is the arcsin one by nikvist
 2 years ago

dumbcowBest ResponseYou've already chosen the best response.1
Use completing the square \[\rightarrow \int\limits_{}^{} \frac{dx}{\sqrt{1(x3)^{2}}}\] ...yeah thats what i got
 2 years ago

eistein+newton+gallileo=_meBest ResponseYou've already chosen the best response.0
CAN YOU PLEASE EXPLAIN
 2 years ago

nikvistBest ResponseYou've already chosen the best response.1
\[\int\frac{1}{\sqrt{1x^2}}dx=\arcsin{x}+C\] basic integral
 2 years ago

dumbcowBest ResponseYou've already chosen the best response.1
u = x3 du = dx \[\rightarrow \int\limits_{}^{} \frac{du}{\sqrt{1u^{2}}}\] u = sin(theta) du = cos(theta) \[\rightarrow \int\limits_{}^{}\frac{\cos(\theta)}{\sqrt{1\sin^{2}(\theta)}}d \theta = \int\limits_{}^{}\frac{\cos(\theta)}{\sqrt{\cos^{2}(\theta)}}d \theta = \int\limits_{}^{}d \theta = \theta+C\] \[\theta = \sin^{1}(u) = \sin^{1}(x3)\]
 2 years ago

eistein+newton+gallileo=_meBest ResponseYou've already chosen the best response.0
so automatically once i see such a question i should use trig substitutions ? what about this one 4/(4x^2)
 2 years ago

LagrangeSon678Best ResponseYou've already chosen the best response.0
integral for arc sin is \[\int\limits_{}^{} du/\sqrt{a^2u^2}\]
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.