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eistein+newton+gallileo=_me
Group Title
find the integral of 1/root(x^2 + 6x  8)
with explanations
 3 years ago
 3 years ago
eistein+newton+gallileo=_me Group Title
find the integral of 1/root(x^2 + 6x  8) with explanations
 3 years ago
 3 years ago

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LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
thats the integral?
 3 years ago

Izzy25 Group TitleBest ResponseYou've already chosen the best response.0
i got the information from here: :/ idk tho http://mathforum.org/library/drmath/view/64571.html
 3 years ago

nikvist Group TitleBest ResponseYou've already chosen the best response.1
\[\int\frac{1}{\sqrt{x^2+6x8}}dx=\int\frac{1}{\sqrt{x^2+6x9+1}}dx=\int\frac{1}{\sqrt{1(x3)^2}}dx=\] \[=\arcsin{(x3)}+C\]
 3 years ago

eistein+newton+gallileo=_me Group TitleBest ResponseYou've already chosen the best response.0
no the answer is the arcsin one by nikvist
 3 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
Use completing the square \[\rightarrow \int\limits_{}^{} \frac{dx}{\sqrt{1(x3)^{2}}}\] ...yeah thats what i got
 3 years ago

eistein+newton+gallileo=_me Group TitleBest ResponseYou've already chosen the best response.0
CAN YOU PLEASE EXPLAIN
 3 years ago

Izzy25 Group TitleBest ResponseYou've already chosen the best response.0
he wants you to explain
 3 years ago

nikvist Group TitleBest ResponseYou've already chosen the best response.1
\[\int\frac{1}{\sqrt{1x^2}}dx=\arcsin{x}+C\] basic integral
 3 years ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.1
u = x3 du = dx \[\rightarrow \int\limits_{}^{} \frac{du}{\sqrt{1u^{2}}}\] u = sin(theta) du = cos(theta) \[\rightarrow \int\limits_{}^{}\frac{\cos(\theta)}{\sqrt{1\sin^{2}(\theta)}}d \theta = \int\limits_{}^{}\frac{\cos(\theta)}{\sqrt{\cos^{2}(\theta)}}d \theta = \int\limits_{}^{}d \theta = \theta+C\] \[\theta = \sin^{1}(u) = \sin^{1}(x3)\]
 3 years ago

eistein+newton+gallileo=_me Group TitleBest ResponseYou've already chosen the best response.0
so automatically once i see such a question i should use trig substitutions ? what about this one 4/(4x^2)
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
integral for arc sin is \[\int\limits_{}^{} du/\sqrt{a^2u^2}\]
 3 years ago
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