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|dw:1315244053369:dw|

ok well ur gonna end up with this here hold on

20-(5x-25)=-5

so then (5x-25)=25

then 5x=50 and then x=10 :)

tht is very confusing to me, wht happened to the fractions?

|dw:1315244980380:dw|

I got (-5)/(5(x-5))

for the LHS or RHS?

mfleisch5's answer is incorrect btw.

oh ok

I trust you can take it from there?

I got (-5)/(5x-25)=(-5)/(5x-25)

how did you get -5/(5x-25) on the left hand side of the equation? can you show me the steps?

I multiplied the 5 and the x-5, then I thought the 4 was negative and added it with the 1

no, draw and show me. I don't understand what you just said.

first off all, 4 is not negative. secondly, that is not how you subtract fractions.

ok what about (-1)/(5(x-25)) = (-1)/(5(x-25))

|dw:1315245667613:dw|

|dw:1315245751739:dw|

no mfleisch5, x=10 is not the correct answer.

how is it not?

I got 15

\[\frac{4}{x-5} = \frac{4}{x-5} \times \frac{5}{5} = \frac{20}{5(x-5)}\]

similarly,
\[\frac{-1}{5} = \frac{-1}{5} \times \frac{x-5}{x-5} = \frac{-(x-5)}{5(x-5)}\]

exactly. and then u multiply the other one by x-5

no, because everything has 5(x-5) so u can take all of the denominators out

so the left hand side is
\[\frac{20-x+5}{5(x-5)} = \frac{25-x}{5(x-5)}\]

now, the right hand side is
\[\frac{-5}{5x-25} = \frac{-5}{5(x-5)}\]

that means
\[\frac{25-x}{5(x-5)} = \frac{-5}{5(x-5)}\]

you get x = 30

got it, wolfgirl?
also, mfleisch5, you are still wrong. follow the steps I have shown.

almost, there are a lot of numbers

no. u are wrong. blah.

ignore mfleisch5, ignore the pictures I drew, just follow the steps I have shown

Let me know if you have any difficulties.

alright I got it thanks :)

which is a contradiction. therefore x = 10 is not the correct answer.

ok cool