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  • 4 years ago

(2x^2y^-5)(6x^-3y)(1/3 x^-1y^3)? I got 6/x^2y but I don't think that's correct.

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  1. a123
    • 4 years ago
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    that's \[(2x^2y^-5)(6x^-3y)(\frac13x^-1y^3)\] by the way

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